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exis [7]
3 years ago
6

Simplify 288x1318-288x1316

Mathematics
2 answers:
Lerok [7]3 years ago
3 0

Answer:

The answer is 576

Step-by-step explanation:

Katyanochek1 [597]3 years ago
3 0

Answer:

576

Step-by-step explanation:

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A club swimming pool is 23 ft wide and 33 ft long. the club members want an exposed aggregate border in a strip of uniform width
emmasim [6.3K]

Let x = the width of the border

2x+23) by (2x + 33) are the overall dimensions of the pool and the border. Use the area to find x!

Overall area - pool area = 660 sq/ft (aggregate area)

(2x+23)*(2x+33) - (23*33) = 660

Solve.

4x^2+112x = 660

4x^2+112x−660=0 → subtract 660 on both sides

4(x−5)(x+33)=0 → factor

x−5=0 or x+33=0 → set both factors equal to 0

x = 5 or x = -33

In this case, we would use the positive solution, so the strip can be 5 ft. wide!

I hope this helps :)

6 0
3 years ago
WILL GIVE BRIANIEST PLEASE HELP !!!
gregori [183]

Answer:

C 180-123

Step-by-step explanation:

This is because 180 is what triangles always equal and if one angle is 128 then the rest will be answered from this equation

3 0
3 years ago
A hose dispenses 1,413 cm³ of water every minute into a cone with a radius of 60 cm and a height of 150 cm. How long will it tak
sergejj [24]
Hm. Have you ever dispensed water from a hose unto a cone? I know I haven’t, but math can give us a good idea of what it would be like — or at least, how long it would take.

We are told that the hose spills 1413 cm^3 of water every minute. We are also told the cone has a height of 150 cm and a radius of 60 cm. So far, so good.

First things first, we need to find out how much water can fit in the cone. That means volume. The volume of a cone is

π • r^2 • (h/3)

Let’s go ahead and plug in (remember we use 3.14 for π)

(3.14) • (60)^2 • (150/3)

The volume of the cone is 565,200 cm^3

Wait, I’m lost. What were we supposed to do again? Oh, right. We needed to find how long it would take for the hose to fill in the cone. Well, if we know the hose dispenses 1413 cm^3 per minute, and there is a total of 565,200 cm^3 the cone can take, we can divide the volume of the cone by the amount the hose dispenses per minute to get the number of minutes it’d take to fill it.

565200/1413

400 minutes. Wow, ok. I wouldn’t want to wait that long. That’s like watching 3 movies!
7 0
3 years ago
The area of an 14-cm-wide rectangle is 322 cm2. What is its length?<br> The length is<br> cm.
Anika [276]

Answer:

The length of rectangle is 23 cm.

Step-by-step explanation:

<u>DIAGRAM</u> :

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large{14\ cm}}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large{14\ cm}}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Here's the required formula to find the length of rectangle :

{\longrightarrow{\pmb{\sf{A_{(Rectangle)}  = l \times b}}}}

  • A = Area
  • l = length
  • b = breadth

Substituting all the given values in the formula to find the length of rectangle :

\begin{gathered}\qquad{\longrightarrow{\sf{A_{(Rectangle)}  = l \times b}}}\\\\\qquad{\longrightarrow{\sf{322 = l \times 14}}}\\\\\qquad{\longrightarrow{\sf{322 = 14l}}}\\\\\qquad{\longrightarrow{\sf{l =  \dfrac{322}{14}}}}\\\\\qquad{\longrightarrow{\sf{l =  \cancel{\dfrac{322}{14}}}}}\\\\\qquad{\longrightarrow{\sf{l = 23 \: cm}}}\\\\\qquad{\star{\underline{\boxed{\sf{ \pink{l = 23 \: cm}}}}}}\end{gathered}

Hence, the length of rectangle is 23 cm.

\begin{gathered}\end{gathered}

<u>LEARN</u><u> </u><u>MORE</u> :

\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}

\rule{300}{2.5}

6 0
2 years ago
Read 2 more answers
If there is 20 dogs in the shelter and 5 dogs get homes, and then 43 more dogs come. how many dogs are there in the shelter?
kap26 [50]

Answer:

58

Step-by-step explanation:

20-5= 15

15+43= 58

4 0
4 years ago
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