Graph the equation:

1 answer:

7 0

This is a slope intercept form problem! The equation would be modeled as in the image. It would be modeled as so because 2 is the y-intercept, meaning that is where we begin on the graph (the point location is (0,2). From there, we would move up 1 point and to the right 3 points because slope is represented by rise over run. Since 1/3 has a variable beside it, we know 1/3 is the slope. With that being said, the equation would be graphed by starting at (0,2) on the graph and moving up 1 and to the right 3 points each time. If you need any help, let me know and I will gladly assist you.

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Step-by-step explanation:

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$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&& y={{k }}x
\end{array}\\\\
-------------------------------\\\\$

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\begin{cases}
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\\\\\\
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\\\\\\
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\\\\\\
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