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pychu [463]
3 years ago
11

An artist mixes 2 parts blue paint and 3 parts yellow paint to get a shade of green. How many parts blue paint should the artist

mic with 12 yellow paint to get the same shade green
Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0

Answer:

8 blue paint

Step-by-step explanation:

3 yellow paint with 2 blue paint gave the mixture

12 yellow paints will give (12 x 2)/3 blue paint to give the mixture

blue paint required= 24/3 = 8 blue points

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What is 10p-3= 2(12+4p)-7
TiliK225 [7]

Answer:

ans = p=7

Step-by-step explanation:

10p-3=2(12+4p)-7

10p=24+8p-7-3

10p-8p=14

2p=14

p=14/2

<u>p=7</u>

7 0
3 years ago
Read 2 more answers
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
11y^2-19y-10=-4y^2 <br> all real solutions
tangare [24]

Answer:

y=5/3 is the only real solution

Step-by-step explanation:

Solve for y over the real numbers:

11 y^2 - 19 y - 10 = -4 y^2

Add 4 y^2 to both sides:

15 y^2 - 19 y - 10 = 0

The left hand side factors into a product with two terms:

(3 y - 5) (5 y + 2) = 0

Split into two equations:

3 y - 5 = 0 or 5 y + 2 = 0

Add 5 to both sides:

3 y = 5 or 5 y + 2 = 0

Divide both sides by 3:

y = 5/3 or 5 y + 2 = 0

Subtract 2 from both sides:

y = 5/3 or 5 y = -2

Divide both sides by 5:

Answer: |

| y = 5/3 or y = -2/5

4 0
3 years ago
Which of the following integers is a solution to the inequality below?
natta225 [31]
I am not sure, but I checked my answer and I am right. Hope this helps, thank you :) !!

7 0
3 years ago
Yolanda's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Yolanda $5.20 per pound, and t
MAXImum [283]

Answer:

78 pounds

Step-by-step explanation:

Let's say Yolanda makes a pounds of Type A coffee and b pounds of Type B coffee. Since the total number of pounds is 130, we can write the equation:

a + b = 130

We know the cost of Type A coffee is $5.20/lb and the cost of Type B coffee is $4.05/lb, so since the total cost is $586.30, we can write:

5.20a + 4.05b = 586.30

We can now solve the system of equations:

a + b = 130

5.20a + 4.05b = 586.30

Manipulate the first equation by subtracting b from both sides:

a + b = 130

a = 130 - b

Substitute 130 - b for a in the second equation:

5.20a + 4.05b = 586.30

5.20 * (130 - b) + 4.05b = 586.30

676 - 5.20b + 4.05b = 586.30

Move the terms with b to one side:

1.15b = 89.70

b = 78

Thus, Yolanda used 78 pounds of Type B coffee.

<em>~ an aesthetics lover</em>

7 0
3 years ago
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