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elena-14-01-66 [18.8K]
3 years ago
15

Two-fifths of the square of a number j

Mathematics
1 answer:
fredd [130]3 years ago
7 0

Answer:

\frac{2}{5}j^{2}

Step-by-step explanation:

Let

j ------> the number

we know that

The square of a number is equal to multiply the number by itself

so

The square of j is

j*j=j^{2}

so

Two-fifths of the square of a number j is the same that multiply the fraction 2/5 by the square of j

\frac{2}{5}j^{2}

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<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-%2014x%20%2B%2024" id="TexFormula1" title="2x^{2} - 14x + 24" alt="2x^{2} - 14
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Factorized

      =(2x-8)(x-3)

Roots : 4 , 3

Step-by-step explanation:

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2x^2 - 14x + 24 = 2x^2 -6x-8x +24

                     =2x(x-3)-8(x-3)\\=(2x-8)(x-3)

If it is to solve for x :

2x^2 -1 4x + 24 = 0\\(2x-8)(x-3)=0\\2x - 8 = 0 \ , \ x - 3 = 0\\2x = 8 \ , \ x = 3\\x = 4 , 3

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