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geniusboy [140]
3 years ago
6

Absolute value for -7 4/5

Mathematics
2 answers:
liq [111]3 years ago
8 0
7 4/5 because absolute value is whatever the number is, but positive!
Lady_Fox [76]3 years ago
4 0
Take away that negative sign.
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What Difference between hundreds and hundredths?
nordsb [41]

hundred means 100 or 200. Like I have 100 cats.

Hundredth means you have 1/100 of something. I have a peice of pie that is 1/100 of the pie. That means there are 100 pieces of the pie but I only have one out the hundred pieces.

hundred=100

hundredth = 1/100 = 0.01

tenth= 1/10 = 0.1

7 0
2 years ago
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Help meh- im d u m b
nordsb [41]

Answer:

<h2><u>[A] 0</u></h2>

Explanation:

  • <u>Lines of symmetry; A line that cuts a shape exactly in half</u>

If you were to put a line of symmetry down and fold the shape in half on that line, both halves would match exactly.

  • If you were to put a line of symmetry down on <u>this triangle</u> both sides <u>would not match</u>, therefore there are no lines of symmetry.
<h3><u>There are zero lines of symmetry, therefore your answer is [A] 0</u></h3>
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3 years ago
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Identify the percent rate of change in exponential function y=(0.9)
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90

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2 years ago
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How do i do this question ........................,,,,
swat32
You equal each to zero, so -6,0,3,7

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PLEASE HELP ASAP 25 PTS TO RIGHT/BEST ANSWER
Novay_Z [31]
Subtract 1111 from both sides

5{e}^{{4}^{x}}=22-115e​4​x​​​​=22−11


 

Simplify 22-1122−11 to 1111

5{e}^{{4}^{x}}=115e​4​x​​​​=11



 

Divide both sides by 55

{e}^{{4}^{x}}=\frac{11}{5}e​4​x​​​​=​5​​11​​



 

Use Definition of Natural Logarithm: {e}^{y}=xe​y​​=x if and only if \ln{x}=ylnx=y

{4}^{x}=\ln{\frac{11}{5}}4​x​​=ln​5​​11​​



 

: {b}^{a}=xb​a​​=x if and only if log_b(x)=alog​b​​(x)=a

x=\log_{4}{\ln{\frac{11}{5}}}x=log​4​​ln​5​​11​​



 

Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}log​b​​x=​log​a​​b​​log​a​​x​​

x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=​log4​​logln​5​​11​​​​



 

Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}log​b​​x​c​​=clog​b​​x
\log{4}log4 -> \log{{2}^{2}}log2​2​​ -> 2\log{2}2log2

x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=​2log2​


Answer= −0.171
7 0
3 years ago
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