Answer:
Step-by-step explanation:
We can write them both like functions like this
Where
x=input
A=Output A
B=Output B
We want the output of A 3 times the output of B this can be written like this:
we replace with the functions
we solve for x
The output that makes the out put of A 3 times teh output of B is
Rewrite it in the form a^2 - b^2, where a = 2x and b = 5
(2x)^2 - 5^2
Use the Difference o Squares: a^2 - b^2 = (a + b)(a - b)
<u>(2x + 5)(2x - 5) </u>
Solve for y for both equations then equate and solve:
5x + 9y = 160
9y = 160 - 5x
y = 160/9 - 5/9x
9x + 8y = 202
8y = 202 - 9x
y = 202/8 - 9/8x
160/9 - 5/9x = 202/8 - 9/8x (common denominator is 72)
1280/72 - 40/72x = 1818/72 - 81/72x
1818/72 - 1280/72 = 81/72x - 40/72x
538/72 = 41/72x
538 = 41x
538/41 = x
x = 13 5/41
X is 2 more than y
x=2+y
5 years ago (x-5 and y-5)
sum is 30
x-5+y-5=30
x+y-10=30
x=2+y
sub 2+y for x
2+y+y-10=30
2y-8=30
add 8 to both sides
2y=38
divide both sides by 2
y=19
Lindsey is 19
Answer:
The quotient is -3
Step-by-step explanation:
we have

Multiply in cross

Simplify
Remember that

substitute

we know that

substitute
