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kogti [31]
3 years ago
10

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

x =  \frac{ -2 \pm \:  \sqrt{ {2}^{2} - 4 \times 1 \times 10 }  }{2}  \\  \\ x =  \frac{ - 2 \pm 6i}{2}  \\  \\  \boxed{ \red{ \huge{x =  - 1 \pm \: 3i}}}

\boxed{ \red{ \huge{answer = d}}}
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3x +-11 &gt;-20<br> Which is greater than or less than
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2 years ago
How do you get the slope-intercept form for -2x+3y=15? Please show steps and explain
lukranit [14]

To convert an equation to slope intercept form, you have to isolate the y variable.

-2x + 3y = 15

Add 2x to both sides.

3y = 2x + 15

Divide all terms by 3.

<h3>y = 1.5x + 5 is the original equation in slope-intercept form.</h3>

I hope this answers your question!

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3 years ago
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5 0
2 years ago
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What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
The perimeters of the triangles shown below are equal
Naya [18.7K]

Answer:

x=19

Step-by-step explanation:

The perimeter of the right triangle is

P=9+12+15 =36

The perimeter of the left triangle is

P =x-7+ x-7+ x-7 = 3x-21

Set them equal

36 = 3x-21

Add 21 to each side

36+21 = 3x-21+21

57 = 3x

Divide each side by 3

57/3 = 3x/3

19 =x

6 0
2 years ago
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