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kogti [31]
3 years ago
10

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

x =  \frac{ -2 \pm \:  \sqrt{ {2}^{2} - 4 \times 1 \times 10 }  }{2}  \\  \\ x =  \frac{ - 2 \pm 6i}{2}  \\  \\  \boxed{ \red{ \huge{x =  - 1 \pm \: 3i}}}

\boxed{ \red{ \huge{answer = d}}}
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describe whether the association in the scatter plot below is linear or non-linear and positive or negative.​
zhannawk [14.2K]

The scatter plot describes the relationship as a positive, non-linear association. Hence option B is correct.

<h3>What is a scatter plot?</h3>

A scatter plot is a plot mathematical chart or graph that depicts the relationships by the use of dots and shows the two numeric variables.

The dots are positioned on each horizontal and vertical value for an individual. They are used for observing the relationship between the variables. The graph shows are positive but nonlinear association.

Find out more information about the relationship.

brainly.com/question/17986737

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3 0
2 years ago
Can someone pls help me on 4 and 5
never [62]

Answer (4):

a=ub/k because

u=ak/b   (starting equation)

ub=ak    (multiply b to both sides)

a=ub/k   (divide both sides by k)

Answer (6)

x=g+c-y because

g=x-c+y  (starting equation)

x+y=g+c (add c to both sides)

x=g+c-y  (subtract y from both sides)

5 0
3 years ago
How to simplify -3 (4×-5y-5×)
VMariaS [17]
Distribute -3 to the rest of the numbers by multiplying them together. That’s all you need to do you don’t have to solve
6 0
3 years ago
Read 2 more answers
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
if you're at the state fair with some friends and deciding between buying a jumbo pack of 50 ride tickets for $45 or medium pack
Mandarinka [93]
The jumbo pack is a better price!
4 0
2 years ago
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