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IRINA_888 [86]
3 years ago
6

Write two mixed numbers that have a sum of 3

Mathematics
2 answers:
elena55 [62]3 years ago
7 0
1 1/4 + 1 3/4 = 3.

That's because 1/4 + 3/4 = 4/4, which equals 1.

1 + 1 = 2.

Now add the 1 from the 4/4 to the 2, and you get 3.
sineoko [7]3 years ago
5 0
One would be 1 1/2 + 1 1/2
hope that helps you finish your homework! :)
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An advertiser that uses ad scheduling has a custom bid adjustment for 9pm- 12am on weeknights. The normal bid is USD$0.40 and th
nika2105 [10]

Answer:

The answer is option D: the advertiser is bidding $0.70 between 9 pm-12 am on weeknights.

Step-by-step explanation:

The normal bid is $0.40 and the bid multiplier is 75%.

This amount becomes:

0.40+(0.75\times0.40)

= $0.70  (OPTION D)

So, the advertiser is bidding $0.70 between 9 pm-12 am on weeknights.

6 0
3 years ago
What is the solution to (4x – 23) 2 – 3 = 2?
deff fn [24]

Step-by-step explanation:

(4x-23)2-3=2

(4x-23)(-1)=2

4x-23= -2

4x= -2+23

=21

x=21/4

=5.2

4 0
3 years ago
Solve the system of linear equations below by graphing. x-y=17 and 3x+y=3
soldier1979 [14.2K]

Answer:

x=5,y=-12

Step-by-step explanation:

You add the two equations to get: 4x=20

Then you get x=5.

You plug this in to x-y=17 to get y=-12

The answer is x=5 and y=-12

8 0
3 years ago
Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m
andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

   A_1  =  67.58 \ in^2

2

   A_2 =415.4 \ ft^2

3

   A_3  =  8.48 \ cm^2

4

  A_4 =  480.38 \ m^2

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

         A =  \frac{\theta}{360} * \pi r^2

Now at r_1  = 11 in and  \theta_1 =  64^o

       A_1 =  \frac{64}{360} * 3.142  * 11^2

       A_1  =  67.58 \ in^2

Now at  r_2  = 20 ft in and  \theta_2  =  119 ^o

       A_2 =  \frac{119}{360} * 3.142 *  20^2

       A_2 =415.4 \ ft^2

Now at  r_3  = 6.5 cm   and  \theta_3 =  23 ^o

     A_3  =  \frac{23}{360} * 3.142 *  6.5 ^2

      A_3  =  8.48 \ cm^2

Now at  r_4  = 14.2 m   and  \theta_4 = 360 -87 =  273 ^o

         A_4 =  \frac{273}{360}  * 3.142 * 14.2^2

          A_4 =  480.38 \ m^2

6 0
3 years ago
What is the answer to the following problem 2/3+5/9
dusya [7]

Answer:

11/9 or 1 2/9

Step-by-step explanation:

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5 0
3 years ago
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