The estimated total,costs,y, of a child's toy is practally based on the number of batteries used x.The cost of one battery is 0.
1 answer:
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Answer:
Side AC is congruent to side DF
Step-by-step explanation:
We are given that
Side AB=5 cm
BC=6 cm
Side DE=5 cm
Side EF= 6cm
We have to find an additional information would need to prove that by SSS.
When two triangles are congruent by SSS it means three sides of one triangle are congruent to corresponding sides of other triangle.
We have in triangle ABC and triangle DEF
Then ,DEF
Reason: SSS postulates
Answer: Side AC is congruent to side DF
Answer:
B. y=1/3x+4
Step-by-step explanation:
Hi there!
We are given the line PQ and we want to find the line that is perpendicular to it
Perpendicular lines have slopes that are negative and reciprocal. When they are multiplied together, the result is -1
So first, let's find the slope of the line PQ
The point P is given as (-8, 7) and the point Q is given as (-4, -5)
The formula for the slope calculated from two points is where (
) and (
,
) are points
We have the needed information for the slope, but let's label the values of the points to avoid any confusion
x1=-8
y1=7
x2=-4
y2=-5
Now substitute into the formula (m is the slope, and remember: the formula contains SUBTRACTION):
m=
simplify
m=
add
m=-12/4
divide
m=-3
So the slope of the line PQ is -3
As said above, perpendicular lines have slopes that have a product of -1
So to find the slope of the line perpendicular to PQ, use this formula:
-3m=-1
divide both sides by -3
m=1/3
The only line that has a slope of 1/3 is B (y=1/3x+4), so B is the answer.
Hope this helps!
To find the gradient of the tangent, we must first differentiate the function.
The gradient at x = 0 is given by evaluating f'(0).
The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so
Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).
So the point (0, -1) lies on the tangent. Substituting into the tangent equation: