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klio [65]
2 years ago
12

Find tan a and sin b if a=10 and b=7...... please help this is for trigonometry

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0

I think it’s R maybe
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Help pls!!!
SVEN [57.7K]

Answer:

an = -6n + 5.

Step-by-step explanation:

This is an arithmetic sequence with first term a1 = -1 and common difference d = -6

an = a1 + d(n-1)

an = -1 + -6(n - 1)

an = -1 -6n + 6

an = -6n + 5.

3 0
3 years ago
The cheerleader section is on the basketball court. Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards. How man
Lady_Fox [76]

Answer:

The area of the floor space is equal to 5.83 sq yards.

Step-by-step explanation:

Given that,

Each row requires a section of floor that is 1 ¾ yards by 3 ⅓ yards.

We need to find how many square yards of floor space are taken up by one row of cheerleaders.

We know that, the area of a rectangle is given by :

A = lb

So,

A=\dfrac{7}{4}\times \dfrac{10}{3}\\\\A=5.83\ yards^2

So, the area of the floor space is equal to 5.83 sq yards.

5 0
3 years ago
100 points! Mhanifa can you please help? Look at the picture attached. I will mark brainliest!
dimulka [17.4K]

Answer:

1 and 2.

Midpoints calculated, plotted and connected to make the triangle DEF, see the attached.

  • D= (-2, 2), E = (-1, -2), F = (-4, -1)

3.

As per definition, midsegment is parallel to a side.

Parallel lines have same slope.

<u>Find slopes of FD and CB and compare. </u>

  • m(FD) = (2 - (-1))/(-2 -(-4)) = 3/2
  • m(CB) = (1 - (-5))/(1 - (-3)) = 6/4 = 3/2
  • As we see the slopes are same

<u>Find the slopes of FE and AB and compare.</u>

  • m(FE) = (-2 - (- 1))/(-1 - (-4)) = -1/3
  • m(AB) = (1 - 3)/(1 - (-5)) = -2/6 = -1/3
  • Slopes are same

<u>Find the slopes of DE and AC and compare.</u>

  • m(DE) = (-2 - 2)/(-1 - (-2)) = -4/1 = -4
  • m(AC) = (-5 - 3)/(-3 - (-5)) = -8/2 = -4
  • Slopes are same

4.

As per definition, midsegment is half the parallel side.

<u>We'll show that FD = 1/2CB</u>

  • FD = \sqrt{(2+1)^2+(-2+4)^2} = \sqrt{3^2+2^2} = \sqrt{13}
  • CB = \sqrt{(1 + 5)^2+(1+3)^2} = \sqrt{6^2+4^2} = 2\sqrt{13}
  • As we see FD = 1/2CB

<u>FE = 1/2AB</u>

  • FE = \sqrt{(-4+1)^2+(-1+2)^2} = \sqrt{3^2+1^2} = \sqrt{10}
  • AB = \sqrt{(-5 -1)^2+(3-1)^2} = \sqrt{6^2+2^2} = 2\sqrt{10}
  • As we see FE = 1/2AB

<u>DE = 1/2AC</u>

  • DE = \sqrt{(-2+1)^2+(2+2)^2} = \sqrt{1^2+4^2} = \sqrt{17}
  • AC = \sqrt{(-5 +3)^2+(3+5)^2} = \sqrt{2^2+8^2} = 2\sqrt{17}
  • As we see DE = 1/2AC

3 0
3 years ago
Read 2 more answers
Help please!!!!!!!!!!!!!
IRISSAK [1]

Answer:

√20,

√19,

√17,

√23

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
8/9 - 2/3 what is the answer i need help
aivan3 [116]
2/9 is the answer!! (:
6 0
2 years ago
Read 2 more answers
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