If you rounded it it would be 4.6
Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
7*3=21....The first number they would both share would be 7
Answer:
Area = 60.0 units²
Step-by-step explanation:
First, let's find the height of the triangle using Pythagorean Theorem:
Height = √(11² - 8²)
= √57
Height = 7.5 (nearest tenth)
✔️Find the area:
Area = ½*base*height
Base = 2*8 = 16
Height = 7.5
Plug in the values
Area = ½*16*7.5
Area = 60.0 units² (nearest tenth)
