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babymother [125]
3 years ago
9

I WILL GIVE BRAINLIEST!! NO LINKS PLZ 4) Simplify.

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer: \frac{\sqrt{5}}{6}

==================================================

Work Shown:

\frac{\sqrt{10}}{3\sqrt{8}}\\\\\frac{\sqrt{10}*\sqrt{8}}{3\sqrt{8}*\sqrt{8}}\\\\\frac{\sqrt{10*8}}{3\sqrt{8*8}}\\\\\frac{\sqrt{80}}{3\sqrt{64}}\\\\\frac{\sqrt{80}}{3*8}\\\\\frac{\sqrt{16*5}}{24}\\\\\frac{\sqrt{16}*\sqrt{5}}{24}\\\\\frac{4*\sqrt{5}}{24}\\\\\frac{\sqrt{5}}{6}\\\\

Note: In the second step, I multiplied top and bottom by \sqrt{8} to rationalize the denominator.

bezimeni [28]3 years ago
7 0

Answer:

square root of 5 over 6 or 0.37267799…

Step-by-step explanation:

Multiply the numerator and denominator by the conjugate.

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I need help with this question!
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Answer:

A

Step-by-step explanation:

4 0
3 years ago
2q+4q+3 what do it equal
Leto [7]

Add the similar variables (think apple+apple), in this case, we would add 2q+4q.

Well, what is 4 apples plus 2 apples? 6 apples, simply, 6q

Since 3 is without a variable, we will leave it as is

Therefore, 2q+4q+3= 6q+3

Hope this helped :)

8 0
3 years ago
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jok3333 [9.3K]

Answer:

2.14 or 214/100

Step-by-step explanation:

8 0
3 years ago
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The length of a parallelogram's altitude is also called the _____.
uysha [10]
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8 0
3 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean µ, of 1850 pounds, and a standard deviation of 9
saul85 [17]

Answer:

We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased

Step-by-step explanation:

Normal Distribution

Population Mean   μ₀  = 1850 pounds

Standard Deviation   σ  =  90 pounds

Type of test

Null Hypothesis                         H₀     ⇒    μ  =  μ₀

Alternative Hypothesis            Hₐ      ⇒    μ > μ₀

A one tail test  (right)

n = 21  as    n  < 30  we use t-student table

degree of fredom   20  

t = 2.845

Sample mean   μ = 1893

Then, we compute t statistics

t(s)  =  [ 1893 - 1850 ] / 90/ √n

t(s)  =   43 * 4,583 / 90

t(s)  = 197,069 / 90

t(s)  =  2,190

And we compare t  and  t(s)

t(s)  =  2.190

t =  2.845

Then  t(s)  <  t

We are in the acceptance zone, we accept  H₀

5 0
3 years ago
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