Answer:
Mark point E where the circle intersects segment BC
Step-by-step explanation:
Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.
Bill's next step is to mark point E, so he can use it as the center of one of the circles just described.
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<em>Comment on Bill's "technology"</em>
In the technology I would use for this purpose, the next step would be "select the angle bisector tool."
Answer:
Your answer would be D: isometry
Step-by-step explanation:
Answer:
x=5/2, y=-3/2. (5/2, -3/2).
Step-by-step explanation:
2=2y+5
3y-3x=-12
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2-5=2y
2y=-3
y=-3/2
3(-3/2)-3x=-12
-9/2-3x=-12
3x=-9/2-(-12)
3x=-9/2+12
3x=-9/2+24/2
3x=15/2
x=(15/2)/3
x=(15/2)(1/3)
x=15/6=5/2
(x/100-1)(x/100+1)=kx^2-1
(x/100-1)(x/100+1)=(x/100)^2 - 1^2 because it's a difference of squares ( (a-b)(a+b) = a^2-ab+ab-b^2 = a^2 - b^2):
(x/100)^2 - 1^2=kx^2 - 1
(x/100)^2 - 1=kx^2 - 1
(x/100)^2=kx^2
(x^2)/(100^2)=kx^2
1/(100^2)=k
1/10000=k
k=0.0001
