Question

Factorise: 2p² - p - 10

Answer 1

2p₂-p-10
2p₂+4p-5p-10
2p(p+2)-5(p+2)
(p+2)(2p-5)

Answer 2

First split the -p into -5p + 4p:

2p^2 +4p -5p - 10

Then you will notice that 2p is in both of the bits on the left, and -5 on both bits on the right:

2p(p+2) -5(p+2)

Then notice the (p+2) is the same for both, so you can put the 2p and the -5 together:

(2p-5)(p+2)