Just plug the inequality in desmos and you get 7<x<13
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²
80
adding up the numbers 30,20,5,25
maybe im wrong but i hope it helps...
Step-by-step explanation:
1. 6 factors of 2 means, 2 multiplied by itself 6 times. It can be written in the form of exponents as 2⁶.
2. ![2^m{\cdot} 2^n](https://tex.z-dn.net/?f=2%5Em%7B%5Ccdot%7D%202%5En)
The law of exponent is : ![x^a{\cdot} x^b=x^{a+b}](https://tex.z-dn.net/?f=x%5Ea%7B%5Ccdot%7D%20x%5Eb%3Dx%5E%7Ba%2Bb%7D)
So,
![2^m{\cdot} 2^n=2^{m+n}](https://tex.z-dn.net/?f=2%5Em%7B%5Ccdot%7D%202%5En%3D2%5E%7Bm%2Bn%7D)
The correct option is (A).
3. If the power of any number is 0, then the value of that number is equal to 1.
So,
![23^0=1](https://tex.z-dn.net/?f=23%5E0%3D1)
Hence, this is the required solution.