I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.
Answer: n² - 3n - 20 = 0
That doesn't factor so there is no integer n solution.
That means there are no polygons with 10 diagonals.
Suzanne says the two expressions 2(3a – 2) + 4a and 2(5a – 2) are equivalent? Is she correct? Explain why or why not?
1 answer:
Answer:
Suzanne is incorrect.
Step-by-step explanation:
To figure out if the two equations are equivalent, we can simplify each one of them.
Simplifying the first equation, we get:
Simplifying the second equation, we get:
Now that both equations are simplified, we can see that the equations are not equivalent. Suzanne is incorrect.
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The point such that the coordinate is 5;3 is (14, 0)
<h3>Midpoint of coordinates using ratio</h3>The formula for finding the midpoint of a line in the ratio m:n is expressed as:
M(x, y) = {(mx₁+nx₂)/2, (my₁+ny₂)/2,}
Given the coordinate of G and D on the line as G(5, 0) and D(1,0)
Since there is no y-axis, hence;
x = 5(5)+1(3)/2
x = 25+3/2
x = 28/2
x =14
Hence the point such that the ratio is 5;3 is (14, 0)
Learn more on midpoint of a line here: brainly.com/question/5566419
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