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Kay [80]
3 years ago
13

Find the equation for the circle with center (4,-5) and passing through (5,-4)

Mathematics
1 answer:
jasenka [17]3 years ago
7 0

Answer:

  (x -4)^2 +(y +5)^2 = 2

Step-by-step explanation:

The equation of a circle centered at (h, k) through point (p, q) is ...

  (x -h)^2 +(y -k)^2 = (p -h)^2 +(q -k)^2

Filling in your given numbers gives ...

  (x -4)^2 +(y +5)^2 = (5-4)^2 +(-4+5)^2

  (x -4)^2 +(y -5)^2 = 2

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Thankkk you in advance!
mrs_skeptik [129]
<h3>Answer:  22</h3>

===============================================

Explanation:

  • x = measure of angle 1 = angle WXY
  • 2x = twice the measure of angle 1 = measure of angle 2 = angle YXZ

The two angles mentioned combine to form angle WXZ which is 66 degrees.

angle1+angle2 = angle WXZ

x+2x = 66

3x = 66

x = 66/3

x = 22

Angle 1 is 22 degrees and angle 2 is 22*2 = 44 degrees.

Check:

angle1+angle2 = 22+44 = 66 = angle WXZ

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