Suppose we choose a path along the
-axis, so that
:
On the other hand, let's consider an arbitrary line through the origin,
:
The value of the limit then depends on
, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
Answer: 13300
========================================
Work Shown:
A = event that it rains
B = event that it does not rain
P(A) = 0.30
P(B) = 1-P(A) = 1-0.30 = 0.70
Multiply the attendance figures with their corresponding probabilities
- if it rains, then 7000*P(A) = 7000*0.30 = 2100
- if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200
Add up the results: 2100+11200 = 13300
This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.
I think it’s 10 not sure but hope this help
1.26 A. 2 D. This is a filler lol
Answer:
B
Step-by-step explanation:
log4x = 2.1
logx/log4 = 2.1
logx = log(4) x 2.1
logx = 1.264
x = 10^(1.264)
x = 18.38 (to two d.p)
