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kakasveta [241]
3 years ago
15

Waht is 7 divided by 8362

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0
11945714 will be ur answer
Helen [10]3 years ago
4 0
Depends. 7 divided by 8362 or 8362 by 7? here, i can do both.

7 divided by 8362 is 0.0008371203

8362 divided by 7 is 1194.57142857

..just in case you got it backwards, i put both.
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A Gallup survey of 2322 adults (at least 18 years old) in the U.S. found that 408 of them have donated blood in the past two yea
Flura [38]

Answer: (0.163,\ 0.189)

Step-by-step explanation:

The confidence interval for population proportion(p) is given by :-

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} = Sample proportion.

n= Sample size.

z* = Critical value.

Let p = Proportion of adults in the U.S. who have donated blood in the past two years.

As per given , we have

n= 2322

Sample proportion of adults in the U.S. who have donated blood in the past two years. : \hat{p}=\dfrac{408}{2322}\approx0.1757

By z-table , the critical value for 90% confidence : z*= 1.645

Then, the 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years will be

0.1757\pm ( 1.645)\sqrt{\dfrac{0.1757(1-0.1757)}{2322}}

0.1757\pm ( 1.645)\sqrt{0.0000623727433247}

0.1757\pm ( 1.645)(0.00789764163056)

0.1757\pm 0.013

=(0.1757- 0.013,\ 0.1757+ 0.013)

=(0.1627,\ 0.1887)\approx(0.163,\ 0.189)

Hence, the 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years. = (0.163,\ 0.189)

5 0
3 years ago
When testing a claim that the majority of adult Americans are against the death penalty for a person convicted of murder, a rand
Black_prince [1.1K]

Using the z-distribution, it is found that the p-value is of 1.

At the null hypothesis, it is tested <u>that the majority is not against the death penalty</u>, that is:

H_0: p \neq 0.5

At the alternative hypothesis, it is <u>tested that the majority is against the death penalty</u>, that is:

H_1: p > 0.5

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are: \overline{p} = 0.27, p = 0.5, n = 491.

Then, the value of the <em>test statistic</em> is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.27 - 0.5}{\sqrt{\frac{0.5(0.5)}{491}}}

z = -10.19

Using a z-distribution calculator, for a <u>right-tailed test</u>, as we are testing if the proportion is greater than a value, the p-value is of 1.

A similar problem is given at brainly.com/question/16313918

3 0
3 years ago
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