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3 years ago

13

What is the equation of the polynomial function shown on the graph?

1 answer:

gogolik [260]3 years ago

3 0

Answer:

-(x+4)(x+1)(x-3).

Step-by-step explanation:

Let find the roots of the polynomial function. Roots are the x intercept( what is the value of x when y=0)

The roots are -4,-1,and 3. We can represent that as

(x+4)(x+1)(x-3)

This is a negative polynomial so we will reflect it across the x axis by putting a negative sign in front of the roots.

-(x+4)(x+1)(x-3).

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Six months ago you won $1,000,000 on a scratch-off lottery ticket and invested your winnings with a financial advisor at the inv

statuscvo [17]

Answer:

The total worth of the investment after 6 months is T = $ 1004004

The geometric mean of the above monthly returns is $\= G = 0.001$

Step-by-step explanation:

From the question we are told that

The growth for each month are

R1 = -0.4, R2= 0.67, R3 = 1.0, R4 = -0.5, R5 = 0.2, R6 = -0.165

The amount invested is $A = \$ 1,000,000$

The number period of the investment is 6 months

Generally the worth of the investment after each month is

$G_i = G_p * (1 + R_i)$

Here $G_p$ is the worth of the investment the previous year

$R_i$ is the growth for that month

So considering the first month

$G_1 = G_p (1 + R_1)$

Here $G_p = A$

So

$G_1 = 1000000 (1 -0.4)$

$G_1 = 600000$

Considering the second month

Here $G_p = 600000$

So

$G_2 = 600000 (1 + 0.67)$

=> $G_2 = 1002000$

Considering the third month

Here $G_p = 1002000$

So

$G_3 = 1002000 (1 + 1)$

$G_3 = 2004000$

Considering the fourth month

Here $G_p = 2004000$

So

$G_4= 2004000 (1 + -0.5)$

$G_4= 1002000$

Considering the fifth month

Here $G_p = 1002000$

So

$G_5= 1002000 (1 + 0.2)$

$G_5= 1202400$

Considering the six month

Here $G_p = 1202400$

So

$G_6= 1202400 (1 -0.165)$

$G_6= 1004004$

Generally the total worth of the investment after 6 months is T = $ 1004004

Generally the geometric mean of the monthly returns is

$\= G = \sqrt[n]{ [(1 + R_1 ) * \cdots (1 + R_n)} ]-1$

Here n represents the number of months which has a value n = 6

So

$\= G = \sqrt[6]{[(1+ (-0.4 )) * (1 + 0.67) * \cdots * (1 + (-0.165))]} - 1$

$\= G = 0.001$

5 0

3 years ago

How can you get the sauare root

xenn [34]

Well your answer depends on what the initial number is.
example: the square root of 100 is 10. the square root of 144 is 12 and so on

6 0

3 years ago

Read 2 more answers

A newspaper stand sold 1000 copies of the city newspaper for $1600. Write and solve an equation to find the price of one copy.

Goshia [24]

Simple. just do this:
1000x=1600
x=1600÷1000
x=1.6

each newspaper is $1.60

8 0

4 years ago

Read 2 more answers

In the following cylinder shape, if the volume

galben [10]

Answer:

c

Step-by-step explanation:

I just did this question for my math class and i got it right

7 0

2 years ago

A radioactive substance decays according to the following function, where yo is the initial amount present, and y is the amount

antoniya [11.8K]

Answer:

Therefore 10.75 days is the half life of the given radioactive substance.

Step-by-step explanation:

Given that, a radioactive substance decays function is

$y=y_0 \ e^{-0.0645t}$

where y₀= initial amount of radioactive substance

y= The amount of radioactive substance at time t.

t is in days

Half life is the time required to reduce the amount of the substance to its half of the initial amount.

For half life

$y=\frac{1}{2} y_0$

Putting the value of y in the given function

$\frac12y_0=y_0 \ e^{-0.0645t}$

$\Rightarrow \frac12= \ e^{-0.0645t}$

Taking ln both sides

$\Rightarrow ln( \frac12)= ln(e^{-0.0645t})$

$\Rightarrow ln1-ln2=-0.0645t$ [ $\because lne^a=a,$ $ln(\frac ab)= ln \ a- ln \ b$ ]

$\Rightarrow-ln2=-0.0645t$

$\Rightarrow t=\frac{-ln2}{-0.0645}$

=10.75 days.

Therefore 10.75 days is the half life of the given radioactive substance.

8 0

3 years ago