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Elina [12.6K]
3 years ago
9

PLEASE HELP ASAP!!!!!!!! WILL GIVE BRAINLIEST IF YOURE RIGHT!!

Mathematics
1 answer:
Leni [432]3 years ago
4 0
Hello Mate!

Using ( y=mx + b formula, m=slope)

Therefore,we can clearly see that The Correct Answer = Option "C". m=-2.

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Ps. Mark As Brainliest IF Helped!)

-TheOneAboveAll :D
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Pls answer this for meeee​
Roman55 [17]

Answer:

7 hamsters at 5 pesos each and 13 hamsters at 8 pesos each

Step-by-step explanation:

5x + 8y = 139

x + y = 20

x = 20 - y

5x + 8y = 139

5(20 - y) + 8y = 139

100 - 5y + 8y = 139

100 + 3y = 139

3y = 139 - 100

3y = 39

3y/3 = 39/3

y = 13

x + y = 20

x + 13 = 20

x = 20 - 13

x = 7

7 0
2 years ago
A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after
lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                         P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of persons who were still employed primarily as engineers  = \frac{111}{200} = 0.555

           n = sample of graduates = 200

           p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                 significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } , 0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } ]

 = [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0
3 years ago
A line contains the points (-7,15) and (10,27) what is the slope of the line as a simplified fraction? HURRY I NEED HELP
miss Akunina [59]

Hey! I have found that the answer is:

Answer: 12/17

I am from k12 school :)

4 0
3 years ago
what is the distributive property :( i forgot what it was uh mrs. tara falls is killing me with math
jolli1 [7]
Distributive property lets you distribute 3(3+x)

so this is the property, note: xy=x times y=x(y)

a(b+c)=(ab)+(ac)
7 0
3 years ago
Cassie has 10 cousins. There is only 1 Jackson cousin, but there are twice as many Lopez cousins as Chen cousins. How many Lopez
user100 [1]
Jackson = 1
+
Lopez = 6
+
Chen = 3
=
10 cousins
3 0
2 years ago
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