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3 years ago

What is the quotient of 5.46 and 0.006? Please show work and (quotient means division)!!

2 answers:

7 0

5.46 ÷ 0.006 =
= 5 46/100 ÷ 6/1000 =
= 5 23/50 ÷ 3/500 =
= 273/50 * 500/3 =
= 273/1 * 10/3 =
= 273 * 10/3 =
= 2730 / 3 =
= 910

I hope it will help you :)

Bad White [126]3 years ago

7 0

5.46 ÷ 0.006

Now, multiply both the numerator and denominator by 1000. we do this to get a whole number in denominator so that it is easier to solve.

= 5460 ÷ 6
= 910

So, the required quotient is 910

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List all partitions of the set. (a) (1,2) (b) [a, b,c)

Alchen [17]

Answer: Hello mate!

The partition of a set is defined as a partition of the set into a nonempty subset, where the set itself is a subset of himself, then the set is a partition of himself.

a) in this we have a set of two objects; A = (1,2) the partitions of this set are: (∅), (1), (2) and (1,2). Where (∅) is the null set.

b) Now we have a set of three objects; B = (a,b,c) the partitions of this set are: (∅), (a), (b), (c), (a,b), (a,c), (b,c), (a,b,c)

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3 years ago

Does anyone know how to do this please help

ICE Princess25 [194]

Step-by-step explanation:

the photo should explain

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2 years ago

What is the IQR (interquartile range) of the data set? 33, 37, 45, 61, 64, 67

Nataly_w [17]

solution is first os all find median

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4 0

3 years ago

rusak2 [61]

Answer:

(1.13, 7.74) and (-4.13, 18.26)

Step-by-step explanation:

This can be solved in two ways: mathematically and graphically.

Graphing

Plot both lines and find where they intersect. See the attachment.

The intersection points are (1.13, 7.74) and (-4.13, 18.26)

Mathematical

y + 2x = 10

y = 10 - 2x

y = 3x² + 7x - 4

10 - 2x = 3x² + 7x - 4

3x² + 9x - 14 = 0

Solve this using the quadratic equation:

x = 1.13 and -4.13

Use these two values of x to find y:

y = 10 - 2x

y = 10 - 2(1.13)

y = 7.74

y = 10 -2x

y = 10 -2(-4.13)

y = 18.26

The two points are:

(1.13, 7.74) and (-4.13, 18.26)

7 0

2 years ago

Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population

laila [671]

Here we will use exponential form, which is

$y = y_{0} e^{kt}$

Initial value, y0 = 500

Double of 500 = 1000

$1000 = 500e^{k*1}$

$2 = e^k$

$k= ln (2)$

Required equation is

$y=500e^{x ln2} \\ y= 500 (2)^x$

6 0

3 years ago