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3 years ago

In a complex system, many subsystems interact with one another. How do these systems interact in terms of inputs and outputs?

Computers and Technology

1 answer:

Artemon [7]3 years ago

4 0

Answer:

I think in there transmission you know inputs into ports like for their own

Explanation:

likeslike Spanish and is obviously inputs and outputs their portsinto the portsdifferent ports you know

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If not cleared out, log files can eventually consume a large amount of data, sometimes filling a drive to its capacity. If the l

OLEGan [10]

Answer:

Explanation:

The /var subdirectory contains files to which the system writes data during the course of its operation. Hence, since it serves as a system directory, it would prevent log files from consuming a large amount of data.

7 0

3 years ago

Read 2 more answers

Output a table that show the cube of the numbers 1-15<br> (C++)

Rainbow [258]

Answer:

The c++ program to display cube of numbers from 1 to 15 is given below.

#include <iostream>

using namespace std;

int main() {

// variables declared and initialized

int num = 15, k, cube;

cout << " Cubes of numbers from 1 to 15 are shown below " << endl;

for( k = 1; k <= num; k++ )

{

// cube is calculated for each value of k and displayed

cube = k * k * k ;

cout << " \t " << cube << endl;

}

return 0;

}

OUTPUT

Cubes of numbers from 1 to 15 are shown below

125

216

343

512

729

1000

1331

1728

2197

2744

3375

Explanation:

The variables are declared and initialized for loop, cube and for condition in the loop – k, cube, num respectively.

Inside for loop which executes over k, beginning from 1 to 15, cube of each value of k is calculated and displayed. The loop executes 15 times. Hence, cube for numbers from 1 to 15 is displayed after it is calculated.

for( k = 1; k <= num; k++ )

{

cube = k * k * k ;

cout << " \t " << cube << endl;

}

In the first execution of the loop, k is initialized to 1 and variable cube contains cube of 1. Hence, 1 is displayed on the screen.

In the second execution, k is incremented by 1 and holds the value 2. The variable cube contains cube of 2, which is calculated, and 8 gets displayed on the screen.

After each execution of the loop, value of k is incremented.

After 15 executions, value of k is incremented by 1 and k holds the value 16. This new value is greater than num. Hence, the loop terminates.

3 0

3 years ago

Diana is running a successful remarketing campaign. She wants to expand her reach with other targeting options. While creating a

mart [117]

Answer:

B: Audience interest around different topics.

Explanation:

When using Google Ads, and the main aim is to create a campaign for a particular marketing activity, there are several options that makes Google Ads the ideal application for this purpose. However, choosing similar audiences under the targeting option is simply telling google to find users or audiences that are interested in the different topics, but are in one way or the other connected to your marketing activity or campaign.

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3 years ago

Identify the root folder in the absolute path /folder1/folder2/folder3/file.

Lilit [14]

Absolute path always start from the root folder.
folder 1 /folder 2 / folder 3 / file.
Here the path start from folder 1, which is the root folder.
Folder 2 and folder 3 are the sub-folders.

Answer: Folder 1

3 0

3 years ago

Read 2 more answers

Assign a pointer to any instance of searchChar in personName to searchResult.#include #include using namespace std;int main() {c

Firlakuza [10]

Answer:

Here it the solution statement:

searchResult = strchr(personName, searchChar);

This statement uses strchr function which is used to find the occurrence of a character (searchChar) in a string (personName). The result is assigned to searchResult.

Headerfile cstring is included in order to use this method.

Explanation:

Here is the complete program

#include<iostream> //to use input output functions

#include <cstring> //to use strchr function

using namespace std; //to access objects like cin cout

int main() { // start of main() function body

char personName[100]; //char type array that holds person name

char searchChar; //stores character to be searched in personName

char* searchResult = nullptr; // pointer. This statement is same as searchResult = NULL

cin.getline(personName, 100); //reads the input string i.e. person name

cin >> searchChar; // reads the value of searchChar which is the character to be searched in personNa,e

/* Your solution goes here */

searchResult = strchr(personName, searchChar); //find the first occurrence of a searchChar in personName

if (searchResult != nullptr) //if searchResult is not equal to nullptr

{cout << "Character found." << endl;} //displays character found

else //if searchResult is equal to null

{cout << "Character not found." << endl;} // displays Character not found

return 0;}

For example the user enters the following string as personName

Albert Johnson

and user enters the searchChar as:

Then the strchr() searches the first occurrence of J in AlbertJohnson.

The above program gives the following output:

Character found.

8 0

3 years ago