A line contains the point (8, –5). If the slope of the line is 5/7 write the equation of the line using point-slope form.

Point A is the incenter of ΔDEF. What is the length of NA?

azamat

LA = NA = MA

5x - 1 = 6x - 3

-x = -2

x = 2

LA = 5x - 1

LA = 5(2) - 1 = 9

NA = 9

5 0

3 years ago

Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

. In April, it rained 1/4 of an inch on 15 different days. How many inches of rain fell

notka56 [123]

Answer:

3.75, or $\frac{15}{4}$ inches of rain during the 15 days of April.

Step-by-step explanation:

All you have to do is add $\frac{1}{4}$ 15 times to get that number.

$\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ + $\frac{1}{4}$ = 3.75

You can also do 15 times $\frac{1}{4}$ , which will result in the same thing.

#teamtrees #WAP (Water And Plant)

5 0

3 years ago

Arthur’s employer withheld $15987.76 in federal income tax. After completing his return, Arthur has determined that his tax is $

Lerok [7]

I don’t know the answer

6 0

2 years ago

the hundreds digit of my number is greater than the 10 digit. the one digit is less than the ten digit. what could my number be

muminat

<span>h > t, u < t can be written together either of these two ways:
u < t < h or h > t > u And it could be any of these 120 numbers:
210 310 320 321 410 420 421 430 431 432 510 520 521 530 531 532 540 541 542 543 610 620 621 630 631 632 640 641 642 643 650 651 652 653 654 710 720 721 730 731 732 740 741 742 743 750 751 752 753 754 760 761 762 763 764 765 810 820 821 830 831 832 840 841 842 843 850 851 852 853 854 860 861 862 863 864 865 870 871 872 873 874 875 876 910 920 921 930 931 932 940 941 942 943 950 951 952 953 954 960 961 962 963 964 965 970 971 972 973 974 975 976 980 981 982 983 984 985 986 987
</span>

6 0

3 years ago