Whitch expression is equivalent to 7 to the 3rd power? 7*7*7. Or 21. Or. 3 to the power of. Or. 10

Armando got a job selling bags of peanuts at the local art festival. He is paid a fixed amount of $320 per

skelet666 [1.2K]

0.67n + 320

=(0.67 * 430) + 320

= 288.1 + 320

= $608.1

0.67n + 320 = 728.70

0.67n = 728.70 - 320

0.67n = 408.7

n = 408.7 / 0.67

n = 610 Bags of peanuts

6 0

2 years ago

Select the correct answer. A model rocket was launched from the top of a building. The rocket's approximate height can be modele

garri49 [273]

Answer:

13 seconds.

Step-by-step explanation:

Given

$h = -4.9(t - 13)(t + 2).$

Required

Determine a reasonable solution for t

To do this, we equate h to 0.

$h = -4.9(t - 13)(t + 2).$ becomes

$0 = -4.9(t - 13)(t + 2).$

Divide through by -4.9

$0 = (t - 13)(t + 2).$

Reorder the expression

$(t - 13)(t + 2) = 0.$

Split

$t-13 = 0$ or $t + 2 = 0$

This gives:

$t = 13$ or $t = -2$

But time can't be negative, So:

$t = 13$

6 0

2 years ago

What is the interest earned on $20,000 for five years, at an interest rate of 3% compounded daily?

SSSSS [86.1K]

Answer:

The final balance is $23,232.33.

The total compound interest is $3,232.33.

6 0

2 years ago

In an all boys school, the heights of the student body are normally distributed with a mean of 70 inches and a standard deviatio

almond37 [142]

Answer:

0.010

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score = 63 inches

μ is the population mean = 70 inches

σ is the population standard deviation = 3 inches

For x shorter than 63 inches = x < 63

Z score = x - μ/σ

= 63 - 70/3

= -2.33333

Probability value from Z-Table:

P(x<63) = 0.0098153

Approximately to the nearest thousandth = 0.010

Therefore, the probability that a randomly selected student will be shorter than 63 inches tall, to the nearest thousandth is 0.010.

3 0

2 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second