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Dima020 [189]
3 years ago
14

Antonio has a total of 55 marbles. He has 15 green marbles and 12 red marbles. The rest of the marbles are blue. How many blue m

arbles does he have?
A student solves this problem by writing an equation. Which strategy could help check the student’s answer?
Mathematics
2 answers:
mote1985 [20]3 years ago
8 0

Answer:

Antonio has 28 blue marbles

Step-by-step explanation:

Let

x------> the number of green marbles

y------> the number of red marbles

z------> the number of blue marbles

we know that

x+y+z=55 -----> equation A

x=15 ----> equation B

y=12 ----> equation C

Substitute equation B and equation C in equation A and solve for z

15+12+z=55

27+z=55

Subtract 27 both sides

27+z-27=55-27

z=28

scoundrel [369]3 years ago
4 0
Total = green marbles + red marbles + blue marbles
55 = 15 + 12 + blue marbles
55 = 27 + blue marbles
55 - 27 = blue marbles
28 = blue marbles
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Help as soon as possible pleaseee
KiRa [710]

Answer:

(3x + 2)(x-4)

Step-by-step explanation:

3x² - 10x - 8 = 0

(splitting the middle term)

3x² -12x + 2x -8 = 0

3x(x-4) + 2(x-4) = 0

(3x + 2)(x-4) = 0

(3x + 2)(x-4) is the correct answer (option a)

3 0
3 years ago
Read 2 more answers
Were would coordinates 8,7 be after a feflection over the x axis
Svet_ta [14]

Answer:

(8, -7)

Step-by-step explanation:

well since it flip over the x-axis only, the 8 stays the same, however, the 7 flips completely to the second quadrant and becomes -7.

Hope this helped and have a amazing day.

3 0
3 years ago
PLSS WHAT IS THE ANSWER
Ket [755]
It’s negative by the looks of it.

If you solve it you get -2.5

I hope it’s correct!
6 0
2 years ago
Read 2 more answers
part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

8 0
3 years ago
Please help!!! All these need to be simplified
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4 0
2 years ago
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