Answer:
The margin of error for the survey is 0.016
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1024
Sample proportion:

We have to find the margin of error associated with a 90% Confidence interval.
Formula for margin of error:


Putting the values, we get:

Thus, the margin of error for the survey is 0.016
Answer:
i would think its C
Step-by-step explanation:
the other options dont make sense lol
hope this is correct and helps :)
Answer:
d= -5
Step-by-step explanation:
Answer:
0.623 is the probability that between 800 and 850 files get damaged.
Step-by-step explanation:
We are given the following information:
We treat virus can damage computer as a success.
P( virus can damage computer) = 35% = 0.35
The conditions for normal distribution are satisfied.
By normal approximation:

We have to evaluate probability that between 800 and 850 files get damaged.


0.623 is the probability that between 800 and 850 files get damaged.
Answer:
(6,3)
Step-by-step explanation:
y=2/3 x - 1
y=-1/2 x + 6
Since both equations are equal to y, we can set them equal
2/3 x - 1 =-1/2 x + 6
We have fractions, so I will multiply by 6 to clear the fractions
6(2/3 x - 1) =(-1/2 x + 6)6
Distribute
4x -6 = -3x +36
Add 3x to each side
4x+3x -6 = -3x+3x +36
7x -6 = 36
Add 6 to each side
7x-6+6 = 36+6
7x = 42
Divide each side by 7
7x/7 = 42/7
x =6
Now we need to find y
y =2/3x -1
y = 2/3(6) -1
y = 4-1
y=3
(6,3)