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Zielflug [23.3K]
3 years ago
9

What is 2/5 of a book to 1/2 of an hour as a unit rate?

Mathematics
1 answer:
hjlf3 years ago
6 0

Answer: 4/5 book per hour

Step-by-step explanation:                                                                        in this question, we are to rewrite (2/5)/(1/2) as unit rate.

To write this as a unit rate, what we need to do  is to divide 2/5 by 1/2.

That means 2/5 divided by 1/2

Removing the division and replacing with multiplication will give 2/5 * 2/1 = 4/5 books/hour

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What is the solution to the equation - 4 = 6?
balandron [24]

Answer:

10

Step-by-step explanation:

Because 6+4 is 10. When u do these look at the number u know and add them together to get the first number

8 0
3 years ago
Prove, using the second derivative, that the general quadratic y= ax^2+bx+c, is:
lozanna [386]

There are three things you have to know:

  • A function is convex when its second derivative f''(x)>0
  • A function is concave when it second derivative f''(x)
  • The derivative of a power, x^n, is nx^{n-1}

So, the first derivative is

y'=2ax+b

and the second derivative is

y''=2a

This implies that the second derivative of a parabola is constant, and of course that 2 doesn't change the sign of a.

3 0
3 years ago
What is the equation of the linear function represented by the table?
Ad libitum [116K]

Answer:

I can't read that

Step-by-step explanation:

5 0
4 years ago
Is h correct? someone help
Juli2301 [7.4K]

Answer:

No The correct Answer is "G"

Step-by-step explanation:

First lets find 300% as a number which is 3 ok so now

increase 10 by 300%

so 100%+300%=400%

and half of 400 which is 200%

so H is no correct g is

6 0
3 years ago
A man runs to a telephone and back in 15 minutes. His speed on the way to the telephone is 5m/s and his speed on the way back is
xz_007 [3.2K]
This is a distance problem so we can use distance = rate x time.

Given: the distance to the telephone is the same as the distance back from the telephone.  We also know the two speeds and the total time for the trip.

But first let's convert 15 minutes into seconds:  15*60 = 900 seconds.

So: d = 5(t1)  (t1 is the time he took to run to the telephone)
d = 4(t2) (t2 is the time he took to come back from the telephone
t1 + t2 = 900  or t1 = 900 - t2

Now use substitution:

5t1 = 4t2
5*(900 - t2) = 4t2
4500 - 5t2 = 4t2
4500 = 9t2
500 = t2
So therefore t1 = 400

So the distance to the telephone is 5*400 = 2000 meters
5 0
4 years ago
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