Answer:
a) 95% of the widget weights lie between 29 and 57 ounces.
b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%
c) What percentage of the widget weights lie above 30? about 97.5%
Step-by-step explanation:
The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.
a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.
b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%
c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%
answer:
1/433 (decimal: 0.002309)
step-by-step explanation:
5/2,165
= 1/433
to change 1/433 to decimal we'll divide the numerator by the denominator-
1÷433
=0.00230946882
so we're going to round to the ten-millionths place
5 or more raise the floor, 5 or less let it rest
4>5
so 0.002309
good luck :)
i hope this helps
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have a nice day!
Answer:
its 18
Step-by-step explanation:
6x3=18
Answer:
(f+g)(2) = 10
Step-by-step explanation:
f(x)=2x^2+3x
g(x)=x-2
(f+g)(x) will be sum of f(x) and g(x)
(f+g)(x) = 2x^2+3x + x - 2 = 2x^2+4x - 2
we have to find (f+g)(2), for that we will put x = 2
(f+g)(x) = 2x^2+4x - 2

Thus, (f+g)(2) is 10.