Question

Write an equation in point-slope form of the line having the given slope that contains the given point. then graph the line

Answer 1

Answer:

The line of the equation in the point-slope form of the line passing through the point (3, -1) and having slope 1/2 will be:

$y +1 = \frac{1}{2} (x-3)$

Please check the attached graph.

Step-by-step explanation:

Given

• The slope m = 1/2

• The point (3, -1)

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

• m is the slope of the line

• (x₁, y₁) is the point

In our case:

m = 1/2

The point (x₁, y₁) = (3, -1)

substituting the values m = 1/2 and the point  (x₁, y₁) = (3, -1)  in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y - (-1) = \frac{1}{2} (x-3)$

$y +1 = \frac{1}{2} (x-3)$

Thus, the line of the equation in the point-slope form of the line passing through the point (3, -1) and having slope 1/2 will be:

$y +1 = \frac{1}{2} (x-3)$

Please check the attached graph.