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3241004551 [841]
3 years ago
10

Subtracting integers

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0
1.-5
2.-3
3.13
4.-18
5.8
6.14
7.-15
8.-4
9.-25
10.18
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F (x) = (x - 6)2(x + 2)2
riadik2000 [5.3K]

Answer:

Step-by-step explanaf(x) = (x^{2} - 6x + 36) . (x^{2} + 2x + 4)\\f (x) = (x^{4} + 2x^{3}  + 4x^{2} - 6x^{3} - 12x^{2} - 24x + 36x^{2} + 72x + 144)\\f(x) = (x^{4} - 4x^{3} + 28x^{2} + 48x + 144)

7 0
3 years ago
The problem 7,291 ÷ 19 is solved below using partial quotients. Identify what partial quotient was used in each step. Then, iden
Flauer [41]

Answer:

383.7368421053

Step-by-step explanation:

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5 0
3 years ago
Question 2 Which fraction is greater and why? 1/51 or 1/52​
zheka24 [161]

Answer: 1/51

Step-by-step explanation: 1/51 is cut into bigger pieces. Its like cutting 2 pizza's of the exact same size. If you cut one into 5 pieces and another one into 10. If you take a piece of pizza out of both pizza's then the one cut into 5 pieces would be a ligger size.

8 0
3 years ago
Maya is planning a bridal shower for her best friend. At the party, she wants to serve 3 beverages, 3 appetizers, and 3 desserts
Sophie [7]

Answer: 5808000 ways

Step-by-step explanation:

When it comes to selection, the combination formula is used to calculate the number of ways an item can be selected.

Using the combination formula of picking "r" items from a total of "n" items, the number of ways become:

nCr = n! /(n-r)! × r!

Hence,

to choose 3 different beverages from possible 12 = 12C3 = 220

to choose 3 different appetizers from possible 12 = 12C3 = 220

to choose 3 different deserts from possible 10 = 10C3 =120

Total number of ways to choose this meal = 220 × 220× 120 = 5808000 ways

3 0
4 years ago
The ratio of athletes in the two teams is 3:2. After 12 athletes move from first team to second, the ratio is 5:4. Find the numb
Alex

Answers:

  • team one = 162
  • team two = 108

=========================================================

Explanation:

The ratio 3:2 scales up to 3x:2x for some positive whole number x.

This tells us that the first team has 3x people and the second team has 2x people. We'll subtract 12 from the first team and add 12 to the second team to represent 12 people moving.

  • 3x becomes 3x-12
  • 2x becomes 2x+12

The new team counts 3x-12 and 2x+12 represent team 1 and team 2. Those expressions are in the new proportion 5:4.

This means....

(team 1 new count)/(team 2 new count) = 5/4

(3x-12)/(2x+12) = 5/4

4(3x-12) = 5(2x+12)

12x-48 = 10x+60

12x-10x = 60+48

2x = 108

x = 108/2

x = 54

From this, we then can say:

  • team 1 original count = 3x = 3*54 = 162
  • team 2 original count = 2x = 2*54 = 108

The two subtotals add to 162+108 = 270 players overall.

If we were to subtract 12 from team 1, and add 12 to team 2, then,

  • team 1 new count = 162-12 = 150
  • team 2 new count = 108+12 = 120

The ratio 150:120 then reduces to 5:4 when we divide both parts by the GCF 30. This helps confirm we have the correct answer.

4 0
3 years ago
Read 2 more answers
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