ΔQTR and ΔSTP are similar triangles. The corresponding sides of similar triangles are the same length.
TR = PT
TS = QT
Input the algebraic expression to make an equation system
PT = TR
y = 2x - 1 <em>(first equation)</em>
TS = QT
6x + 13 = 5y
6x - 5y = -13 <span><em>(second equation)</em>
</span>Using subtitution method, subtitute y with 2x - 1 from first equation into the second equation, to find the value of x
6x - 5y = -13
6x - 5(2x - 1) = 13
6x - 10x + 5 = 13
-4x + 5 = 13
-4x = 13 - 5
-4x = 8
x = 8/-4
x = -2
Find y with subtituting x with -2 in the first equation
y = 2x - 1
y = 2(-2) - 1
y = -4 - 1
y = -5
Answer:
x = -2
y = -5
Answer:
B .Each side of the original triangle is 2 times the length of each side of the scale drawing.
TELL ME IF I'M WRONG I THINK IS B
Step-by-step explanation:
Answer:
because after decimal then value 0 dont have meaning
Answer:
D.
Step-by-step explanation:
First try to eliminate answers.
You have to work between 30 and 40 hours to get 1565.
It's not A or B.
Now, you can see that the choices are 31, and 35
1565 is only 15 more than 1550.
It's 31.
Given that the amount of time varies inversely with G.
It can be written as,
![T G=K](https://tex.z-dn.net/?f=T%20G%3DK)
where K is the constant.
We need to determine the time it takes to put out the fire when 200 gallons of water are used.
<u>The value of constant:</u>
When
, we get;
![(12)(8)=K](https://tex.z-dn.net/?f=%2812%29%288%29%3DK)
![96=K](https://tex.z-dn.net/?f=96%3DK)
Thus, the value of constant is 96.
<u>Time taken:</u>
Substituting
and
in the formula
, we get;
![T(2)=96](https://tex.z-dn.net/?f=T%282%29%3D96)
Thus, the time taken to put out the fire using 200 gallons of water is 48 minutes.
Hence, Option B is the correct answer.