Answer:
print("\nWelcome to the impossible quiz!\n")
name = input("What's your name before we get started? ")
print("Nice to meet you, "+ name)
print("\nThe rules are very simple, get the answer right and you get 10 points. You only have one chance to get the answer right, get it wrong and you'll lose 3 points! ")
input("\nReady?\n")
user_score = 0
print("First question: Do slugs have four noses?")
answer = input('Give "F" for False or "T" for True: ')
if answer == "T":
time.sleep(2)
print("Correct, you've gained 10 points!")
user_score += 10
elif answer == "F":
time.sleep(2)
print("Incorrect, you've lost 3 points!")
user_score += -3
Explanation:
Please check the answer. However, if before answer was wrong, and we need to use time.sleep(2) for delaying printing.
The two ways to use the help menu is by searching of the contents or searching the index.
The answer is people. It is because this is the most important element in computer based information as every information being gathered or being delivered by the computer are all base and involves with a person, that is why people are important elements in the information system.
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Ann Write a class named Car that has the following fields: yearMode1. The yearModel field is an int that holds the car's year model. make. The make field is a String object that holds the make of the car, such as "Ford" "Chevrolet", "Honda", etc. speed. The speed field is an int that holds the car's current speed. In addition, the class should have the following methods . Constructor. The constructor should accept the car's year model and make as ments. These values should be assigned to the object's yearModel and make fields. The constructor should also assign 0 to the speed field. Accessor. The appropriate accessor methods get the values stored in an object's yearModel, make, and speed fields. , accelerate. The accelerate method should add 5 to the speed field each time it is called _________. brake. The brake method should subtract 5 from the speed field each time it is called.
Answer:
11,424,400 possible passwords
Explanation:
Since all characters are letters and only lowercase
we have 26∧4 = 456,976 possibilities
For a 5-character password which is still lower case sensitive.
we have 26∧5 = 11,881,376 possibilities
Many more possible passwords = (11881376-456976)
= 11,424,400 possible passwords
