Create a python program that display this

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Which term describes the process of training a machine to do simple, repetitive tasks, and adapt or correct its performance base

yKpoI14uk [10]

Automation. ... It involves taking a machine or software that was taught to do simple repetitive tasks (traditional automation) and teaching it to intuitively adapt or correct its performance based on changing conditions, at speed and scale.

8 0

2 years ago

Which of the following is not one of the four methods for classifying the various instances of malware by using the primary trai

BlackZzzverrR [31]

Answer: Source

Explanation: The malware is the software persisting malicious approach to cause the damage/loss.The primary trait of the malware are infection,concealment,etc.

The concealment refer to the malware such as the Trojan horse, and other viruses that has only purpose to cause the malfunctioning in the system.The virus that get into the other software and then damage the system in known as the infectious malware .

The circulation is the transferring of the virus in the circular manner between the system for the damaging.Thus,the only trait that is not the part of the malware is source.

4 0

3 years ago

Assume that ip , jp , and tp have all been declared to be pointers to int and that result has been declared to be an array of 10

natita [175]

Answer:

The code to this question can be given as:

code:

tp = ip;

ip = jp;

jp = tp;

Explanation:

In this question, it is defined that write code for swapping values that swap the pointers, not the values they point to. So in this code, we assume that all the variable and its value is defined. we simply use the swapping rule that is the first value holds in the new variable and second value hold on the first variable and in the last second variable holds the value of the new variable. In this code, the value will be interchanged or swapped.

3 0

3 years ago

Address Resolution Protocol (ARP) is a protocol for mapping an IP address to a physical machine address that is recognized in th

Nimfa-mama [501]

Answer: Switch

Explanation: ARP spoofing is a illegal harmful activity in a disguised manner by a person who tries to send the ARP (Address resolution protocol)request.The disguised ARP request is sent to steal the confidential data by the overloading of the switch because of the numerous amount of the ARP request. This attack is done in the local area network .Therefore, the correct option is switch.

6 0

2 years ago