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3 years ago

Choose the possible descriptions of cross sections formed by the intersection of a plane and a cylinder choose all that apply

Mathematics

1 answer:

nasty-shy [4]3 years ago

7 0

Answer:

circle and rectangle

Step-by-step explanation:

we know that

A cross section that is perpendicular to the base of cylinder is a rectangle

A cross section that is parallel to the base of cylinder is a circle

A cross section that is angled to the base of cylinder is an oval

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A cylinder with 3 radius and and height is 2 inches what is the volume?

VashaNatasha [74]

Answer:

$\huge\boxed{\sf V = 56.5 \ in.^3}$

Step-by-step explanation:

Radius = r = 3 in.

Height = h = 2 in.

<u>Volume:</u>

$\sf Volume \ of \ the \ cylinder = \pi r^2 h\\\\V = (3.14)(3)^2(2)\\\\V =(3.14)(9)(2)\\\\V = (3.14)(18)\\\\V = 56.5 \ in.^3\\\\\rule[225]{225}{2}$

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2 years ago

Michael stands 10 feet from a table, and notices a plate resting on the edge of the table. The top of the table is 3 feet high,

Aleks04 [339]

Answer:

Step-by-step explanation:

quick mafs

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3 years ago

A sample of 8 pieces of data is collected and we wish to perform the level test vs. . The population standard deviation is known

Sphinxa [80]

Answer:

0.0009

Step-by-step explanation:

$\mu=4$

$\sigma=0.55$

n = 8

This is the left tailed test .

The null and alternative hypothesis is ,

$H_0:\mu=4$

$Ha:\mu$

Test statistic = z=-3.12 from the table.

P(z <-3.12 ) = 0.0009

P-value =0.0009

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3 years ago

What is log15 2^3 rewritten using the power property?

OlgaM077 [116]

ANSWER

$log_{15}( {2}^{3} ) = 3 \: log_{15}( {2} )$

EXPLANATION

According to the power property of logarithms:

$log_{x}( {y}^{n} ) = n \: log_{x}( {y} )$

The given logarithm is

$log_{15}( {2}^{3} )$

When we apply the power property to this logarithm, we get,

$log_{15}( {2}^{3} ) = 3 \: log_{15}( {2} )$

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3 years ago

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What 3D shapes can you find around your kitchen? e.g. a tin of baked bean , a box of careal

Paul [167]

Answer:

i would a say Microwave

Step-by-step explanation:

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3 years ago

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