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2 years ago

A cylinder with 3 radius and and height is 2 inches what is the volume?

Mathematics

1 answer:

VashaNatasha [74]2 years ago

3 0

Answer:

$\huge\boxed{\sf V = 56.5 \ in.^3}$

Step-by-step explanation:

Radius = r = 3 in.

Height = h = 2 in.

<u>Volume:</u>

$\sf Volume \ of \ the \ cylinder = \pi r^2 h\\\\V = (3.14)(3)^2(2)\\\\V =(3.14)(9)(2)\\\\V = (3.14)(18)\\\\V = 56.5 \ in.^3\\\\\rule[225]{225}{2}$

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Find the difference quotient and simplify your answer. f(x) = 4x − x2, f(4 + h) − f(4) h , h ≠ 0

Anon25 [30]

The difference quotient and simplification will be = [4 -h-2x]

The given equation is as follows: f(x)= 4x - x²

For finding the quotient and further simplification we must follow the following steps:

[f(x + h) - f(x)] / h = [4(x + h) - (x + h)² - 4x + x²]/ h

<h3>What is simplification of algebraic operations?</h3>

Getting the functions in their lowest terms is known as simplification.

Brackets will get open and solved further;

[f(x + h) - f(x)] / h = [4(x + h) - (x + h)² - 4x + x²]/ h

[f(x + h) - f(x)] / h = [4h - h² - 2x]/ h

Finally dividing the whole equation with h;

= [4 - h - 2x]

Learn more about algebraic operations,

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# SPJ1

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1 year ago

For a standard normal distribution,Find P(-1.21 < Z< 2.26)

Mars2501 [29]

Answer:

The range of z-score is given below as

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1 year ago

Whats the action “verb of the boy runs into the woods”? Please help

Brilliant_brown [7]

Answer:

the boy runs onto the woods

Step-by-step explanation:

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so the answer is runs

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3 years ago

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$