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Alecsey [184]
3 years ago
5

The length and width of a rectangle are measured as 27 cm and 50 cm, respectively, with an error in measurement of at most 0.1 c

m in each. Use differentials to estimate the maximum error in the calculated area of the rectangle.
Mathematics
1 answer:
Tomtit [17]3 years ago
7 0

Answer:

7.7cm

Step-by-step explanation:

Area of a rectangle is expressed as

A = Length × Width

A = LW

Let dL and dW be the errors in the measurements.

If there is an error of at most 0.1cm each in the measurement, then dL = dW = 0.1cm.

The area of the rectangle with error will be expressed as A = LdW + WdL

Given L = 27cm and W = 50cm

A = 27(0.1)+50(0.1)

A = 2.7+5.0

A = 7.7cm

Hence, the maximum error in the calculated area of the rectangle is 7.7cm

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The components of a vector are Ax = –10 units and Ay = 8 units. What angle does this vector make with the positive x axis? g
Mandarinka [93]

Answer:

This vector make an angle of 141° with the positive x axis

Step-by-step explanation:

Refer the attached figure

Components of vector :

A_x=-10 \\A_y = 8

We are supposed to find  What angle does this vector make with the positive x axis

tan \theta =\frac{A_y}{A_x}\\tan \theta =\frac{8}{-10}\\\theta =tan^{-1}(\frac{8}{-10})\\\theta =tan^{-1}(\frac{8}{-10})=-38.65^{\circ}

Now ,

\alpha = 180-38.65=141.35^{\circ}

So, this vector make an angle of 141° with the positive x axis

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3 years ago
Kiero saber la tabla numérica de 14
Arte-miy333 [17]
I think it is 8 right i not sure
8 0
3 years ago
Easy :)<br> solve any ones you want
liberstina [14]

Answer:

3. D, Additive Property of Equality

4. x < 2

5. attached graph

Step-by-step explanation:

3. Additive Property of Equality: this means that you can add/subtract a number from one side, as long as you can do it to the other. as shown in steps 4 and 5, this is what they have done in order to get x by itself.

4. to solve -3x + 8 > 2x - 2, we want to get <em>x</em> by itself on one side. we can treat the inequality sign as an equal sign to solve

-3x + 8 > 2x - 2 < -- subtract 8 from both sides to get -3x alone

-8                -8

-3x > 2x - 10 < -- subtract 2x from both sides to get 2x with the -3x

-2x   -2x

-5x > -10 <-- divide both sides by -5 to get <em>x</em> alone

when we divide by a negative number in an inequality, we flip the sign. so > becomes < once we divide by -5. this is important to ensure we get the right answer

-5x/-5 = x

-10/-5 = 2

x < 2

this inequality means that any value for <em>x</em> has to be <em>less than</em> 2 in order for the inequality to be true

on a number line it would look like the following:

<---------------2) - - - - - - - - >

the numbers to the left of 2 would be shaded in, as those are less than 2. the number 2 would have either an open circle on top of it or a parentheses facing to the left, either one works.

5. to graph y < 2/5x - 4, we want to get this equation into slope intercept form which is y = mx + b, where mx is the slope and b is the y-intercept

again, treat the inequality symbol as an = sign in this case and solve to get y by itself

y = 2/5x - 4 <--- this is already in slope intercept form, so we do not need to solve for y in this case.

to graph this, we would need to start at the y-intercept which is (0, -4). i will attach a graph to make this a bit easier visually

from there, you would use the slope to find another point on the graph. the slope is rise/run which also means y/x.

so you would need to go 2 units up from (0, -4), and 5 units right from where you landed

since this is an inequality, we will need to find any answers on the graph that satisfy the inequality by shading in the region where those points are solutions.

to do this we need to find a test point. a test point tells us whether or not that point and anything in its section is included in the solution. if the inequality is true with the test point, that answer and anything in that section is included in the answer. if its false, that point and everything in that section is not included.

you can always use the origin (0,0) if its not graphed on the line. in this case, we will use the origin as a test point. so plug in the test point into the original inequality

y < 2/5x - 4

0 < 2/5(0) - 4

0 < -4 <-- this is false and (0,0) and anything in its section is not included as a solution, so you would shade below the line as (0,0) was above the line, and anything above the line cannot be used as a solution to the inequality

graph the line connecting the two points using a dotted line as the inequality symbol is <, meaning points on that line are not solutions to the inequality

with the graph i attached, shade in the entire dark blue area. the graph is a bit rough but your graph should look similar to that

4 0
3 years ago
a memory is a memory from a real event that was encoded, stored, but not retrieved for a long period of time; it is retrieved af
Inga [223]

Implicit or Doubtful memory of actual events that was stored encrypted, but was not retrieved for a long time until subsequent events suddenly brought it back to consciousness. The establishing, stabilizing like processes include in this memory.

Implicit Memory is a type of long-term memory and it is also known as unconscious memory or automatic memory. Implicit memory draws on past experiences to remember things without thinking. The power of tacit memory is made possible by past experiences, regardless of how long ago those experiences were.

Second stage of long-term memory formation.

Implicit memory, a subset of procedural memory, allows you to perform many everyday physical activities, such as walking and cycling, without having to think about it. Most of the implicit storage is procedural in nature.

For example:

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To learn more about Implicit Memory, refer:

brainly.com/question/15033888

#SPJ4

5 0
1 year ago
Plz help and explain
Westkost [7]

Answer:  B

<u>Step-by-step explanation:</u>

In order to get the best representative sample, you should choose the widest range of students, which is from a random sample of all students.

(A) Choosing from only the 6th graders, eliminates the choices the other grade-level students would choose.

(C) Choosing only from students who participate in after-school activities, eliminates the choices the other students would choose.

(D) Chhosing only from students not participating in the fundraiser is silly since you want to know what the students participating in the fundraiser would choose.

The only possible option is B - students from all grades, regardless of whether or not they participate in after-school activities.

5 0
3 years ago
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