Find all the areas and add them together
Base Rectangle : LxW = 14 x 12 = 168
Bases Triangles (2) 2x (8x12)/2 = 96
2 Lateral rectangles 14x10 =140 (double) = 280
Surface Area = 168 +96 + 280 = 544
Answer:
It looks like you cut off part of the questions...
Step-by-step explanation:

$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
You could better find the answer at
https://answers.yahoo.com/question/index?qid=20110628190101AAKUGSE
where someone else has already figured it out