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vampirchik [111]
3 years ago
14

Find the solution to the system of equations graphed here.

Mathematics
2 answers:
svp [43]3 years ago
4 0

This can be solved by finding their point of intersection on the graph, which is at point (1,3).

polet [3.4K]3 years ago
3 0
There is no picture, but you would substitute the first number for the x and the second for the y
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3 hundred thousand 3 thousand 8 hundred 4 tens
alekssr [168]

Answer:

3384

Step-by-step explanation:

3 0
2 years ago
Which equation can be used to calculate the surface area of the triangular prism net show below?
enyata [817]

Given:

Net of a triangular prism

To find:

Which equation can be used to calculate the surface area of the triangular prism.

Solution:

Using formulas:

Area of rectangle = length × width

Area of triangle = \frac{1}{2}\times b\times h

Area of left triangle = \frac{1}{2}\times 5\times 12

Area of right triangle = \frac{1}{2}\times 5\times 12

Area of bottom = 5 × 10

Area of Middle = 12 × 10

Area of top = 13 × 10

Surface area of triangular prism:

Surface area = Area of left triangle + Area of right triangle + Area of bottom + Area of middle + Area of top

                     $=\frac{1}{2}\times 5\times 10+\frac{1}{2}\times 5\times 10+5\times 10+12\times 10+13\times 10

Replace multiplication by brackets.

                     $=\frac{1}{2}(5)(10)+\frac{1}{2}(5)(10)+5( 10)+12( 10)+13( 10)

The equation can be used to calculate surface area of triangular prism is

$\frac{1}{2}(5)(10)+\frac{1}{2}(5)(10)+5( 10)+12( 10)+13( 10).

5 0
3 years ago
Read 2 more answers
A wind turbine is located at the top of a hill where the wind blows steadily at 12 m/s, and stands 37 m tall. The air then exits
marta [7]

Answer:

Power generated = 4.315 kW

Step-by-step explanation:

Given,

  • speed of wind when enters into the turbine, V = 12 m/s
  • speed of wind when exits from the turbine, U = 9 m/s
  • mass flow rate of the wind, m = 137 kg/s

According to the law of conservation of energy

Energy generated = change in kinetic energy

Since, the air is exiting at same elevation. So, we will consider only kinetic energy.

Energy generated in one second will be given by,

E\ =\ \dfrac{1}{2}.mV^2-\dfrac{1}{2}.m.U^2

   =\ \dfrac{1}{2}\times 137\times (12)^2-\dfrac{1}{2}\times 137\times (9)^2

   =4315.5 J

   = 4.315 kJ

So, energy is generated in one second = 4.315 kJ

Power generated can be given by,

P\ =\ \dfrac{\textrm{energy generated}}{time}

And the energy is generated is already in per second so power generated will be 4.315 kW.

   

   

   

   

   

8 0
3 years ago
45v^10w^4 + 21v^9 help math
Oksana_A [137]

Answer:

If you need to factor it is

=3v^9(15vw^4+7)

Step-by-step explanation:

4 0
3 years ago
In Mr. Romero's auto shop class, the ratio
MrMuchimi

Answer:

boys 5:2 girls

add the ratio parts together

5 + 2 = 7

divide the total number of students by the total number of parts

35/7 = 5

now multiply each part of the ratio by 5

boys 25

girls 10

there are 25 boys

5 0
3 years ago
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