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ELEN [110]
3 years ago
10

el lanzamiento de un dado 5 veces considerando los sucesos a=2,3,2,4,6. halla la probabilidad que el saga el 2. halla la probali

dad de que salga Ñ ha el 5.​
Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

do you mind translating it

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At a rate of 4.25% over 24 months. If he pays $51.00 in interest, what was the original amount of his loan?
Alexxandr [17]
I = PRT.....rearrange.....P = I / RT

P = 51 / (0.0425* 2).....I used 2 because 24 months = 2 yrs
P = 51 / 0.085
P = 600 <===

6 0
3 years ago
Genuinely confused rn
frosja888 [35]

Using it's concept, it is found that the probability that he winds up wearing the white shirt and tan pants is of \frac{1}{8}.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem:

  • For the shirt, there is 4 outcomes, hence the probability of the white shirt is 1/4.
  • For the pair of pants, there are 2 outcomes, blue or tan, hence the probability of tan pants is 1/2.

Since the shirt and the pants are independent, the probability is given by:

p = \frac{1}{4} \times \frac{1}{2} = \frac{1}{8}.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

8 0
1 year ago
A quiz-show contestant is presented with two questions, question 1 and question 2, and she can choose which question to answer f
Mrrafil [7]

Answer:

The contestant should try and answer question 2 first to maximize the expected reward.

Step-by-step explanation:

Let the probability of getting question 1 right = P(A) = 0.60

Probability of not getting question 1 = P(A') = 1 - P(A) = 1 - 0.60 = 0.40

Let the probability of getting question 2 right be = P(B) = 0.80

Probability of not getting question 2 = P(B') = 1 - P(B) = 1 - 0.80 = 0.20

To obtain the better option using the expected value method.

E(X) = Σ xᵢpᵢ

where pᵢ = each probability.

xᵢ = cash reward for each probability.

There are two ways to go about this.

Approach 1

If the contestant attempts question 1 first.

The possible probabilities include

1) The contestant misses the question 1 and cannot answer question 2 = P(A') = 0.40; cash reward associated = $0

2) The contestant gets the question 1 and misses question 2 = P(A n B') = P(A) × P(B') = 0.6 × 0.2 = 0.12; cash reward associated with this probability = $200

3) The contestant gets the question 1 and gets the question 2 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.4×0) + (0.12×200) + (0.48×300) = $168

Approach 2

If the contestant attempts question 2 first.

The possible probabilities include

1) The contestant misses the question 2 and cannot answer question 1 = P(B') = 0.20; cash reward associated = $0

2) The contestant gets the question 2 and misses question 1 = P(A' n B) = P(A') × P(B) = 0.4 × 0.8 = 0.32; cash reward associated with this probability = $100

3) The contestant gets the question 2 and gets the question 1 too = P(A n B) = P(A) × P(B) = 0.6 × 0.8 = 0.48; cash reward associated with this probability = $300

Expected reward for this approach

E(X) = (0.2×0) + (0.32×100) + (0.48×300) = $176

Approach 2 is the better approach to follow as it has a higher expected reward.

The contestant should try and answer question 2 first to maximize the expected reward.

Hope this helps!!!

3 0
3 years ago
What is the midpoint of a segment with These endpoints (-6,-9) and (16,5)
lora16 [44]

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 16 -6}{2}~~~ ,~~~ \cfrac{ 5 -9}{2} \right)\implies \left( \cfrac{10}{2}~~,~~\cfrac{-4}{2} \right)\implies (5~~,~-2)

7 0
2 years ago
(2tens1one) times 10
Elodia [21]

Answer:

210

Step-by-step explanation:

10+10+1=21

21 x 10=210

6 0
3 years ago
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