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2 years ago

Someone interested in an inventory that might be helpful for making a career choice should try ________.

Social Studies

2 answers:

Alinara [238K]2 years ago

5 0

Answer: The Myers-Briggs Type Indicator

Explanation: The Myers-Briggs Type Indicator is the indicator tool that is used for self analyzation and self reporting by taking up survey to know the result about the different psychological choices that people persist while being around in different places in the world and then making conclusion.

According to the situation mentioned in the question about the inventory-interested person, he should use Myers-Briggs Type Indicator for opting about his career path.

AfilCa [17]2 years ago

4 0

The right answer is <em>“Myers-Briggs Personality Type Indicator”.</em> This is a self-report inventory created to identify someone’s personality type, strengths, and favorites. The questionnaire was developed by Isabel Myers and her mother Katherine Briggs with its basis on their work with Carl Jung's theory of personality types. Depending on the answers to the questions on the inventory, people are recognized as having one of 16 personality types. The objective of the MBTI is to allow respondents to additional explore and understand their own personalities together with their likes, dislikes, strengths, weaknesses, possible career preferences, and compatibility with other people.

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Read 2 more answers

Suppose you find a rock that contains 10 micrograms of radioactive potassium-40, which has a half-life of 1.25 billion years. By

attashe74 [19]

Answer:

The rock is 3.75 billion years ago.

Explanation:

Given that:

Half life = 1.25 billion years

1 billion years = 10⁹ years

So,

Half life = 1.25 × 10⁹ years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{1.25\times 10^9}\ year^{-1}$

The rate constant, k = 5.5452 × 10⁻¹⁰ years⁻¹

Initial amount [A₀] = 80 micrograms

Final amount $[A_t]$ = 10 micrograms

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

So,

$10=80\times e^{-5.5452\times 10^{-10}\times t}$

$80e^{-5.5452\times \:10^{-10}x}=10$

$\frac{80e^{-5.5452\times \:10^{-10}x}}{80}=\frac{10}{80}$

$\ln \left(e^{-5.5452\times \:10^{-10}x}\right)=\ln \left(\frac{1}{8}\right)$

$x=\frac{10^{10}\times \:3\ln \left(2\right)}{5.5452}=3.75\times 10^9$

So,

<u>The rock is 3.75 billion years ago.</u>

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2 years ago

1. What materials are required to register to vote in your state?

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Answer:

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Explanation:

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