11x = 44
X=4
44 + 7 = 51
5x = 20
31 + 20 =51
51 = 51
Answer:
J=15t+50
Step-by-step explanation:
The equation to represent this situation will be in the form J=mt+b where b is the starting value of love units, m represents the "love units" that are multiplied by the number of week, t is the number of weeks, and J represents Jack's love at that specific week.
The equation becomes: J=15t+50
To check, the equation should equal 50 when t=0, 65 when t=1, and 80 when t=2.
Checking t=0:
J=15(0)+50=0+50=50
Checking t=1:
J=15(1)+50=15+50=65
Checking t=2:
J=15(2)+50=30+50=80
The equation J=15t+50 does model the behavior of Jack's love at any week t based on the given data. Note that the equation used was based on slope intercept form (y=mx+b) due to the given data having a linear relationship.
Answer:
D 36
Step-by-step explanation:
<em>Write the information algebraically</em>
c = 3a
c + a = 48
c = children, a = adults
<em>In the second sentence (in bold), we can replace c with 3a</em>
c + a = 48 → 3a + a = 48
<em>Simplify</em>
3a + a = 48 → 4a = 48 → a = 12 (divide both sides by 4)
<em>We can then substitute or plug in a = 12 into the original equation:</em>
c + a = 48 → c + 12 = 48 → c = 36 (subtract 12 from both sides)
<h3>There are 36 children</h3>
Answer:
x = 13 ,y = 60
Step-by-step explanation:
Solve the following system:
{2 x + 6 y = 386 | (equation 1)
4 x + 4 y = 292 | (equation 2)
Swap equation 1 with equation 2:
{4 x + 4 y = 292 | (equation 1)
2 x + 6 y = 386 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x + 4 y = 292 | (equation 1)
0 x+4 y = 240 | (equation 2)
Divide equation 1 by 4:
{x + y = 73 | (equation 1)
0 x+4 y = 240 | (equation 2)
Divide equation 2 by 4:
{x + y = 73 | (equation 1)
0 x+y = 60 | (equation 2)
Subtract equation 2 from equation 1:
{x+0 y = 13 | (equation 1)
0 x+y = 60 | (equation 2)
Collect results:
Answer: {x = 13 ,y = 60
Answer:
The horizontal asymptote is y=0