The scale factor of a large swimming pool to a small swimming pool is 0.12. The large swimming pool can hold 15000 m cubed of wa
2 answers:
Answer:
Step-by-step explanation:
Let
x------> the volume of the small swimming pool
y------> the volume of the large swimming pool
z-----> the scale factor
we know that
The volume of the small swimming pool is equal to the scale factor elevated to the cube multiplied by the volume of the large swimming pool
so
In this problem we have
substitute
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Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is
where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A
We do the same for company C
This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A