The answer is that you are measuring "resistance".
If the segment is DE-energized, which means the entire device is shut down, at that point the main thing you can quantify with the meter- probes on the two ends of the segment is its resistance. The ordinary meter measures volts, amps, and ohms. If you touch
the probes to the two ends of the part and the circuit is empowered, at that point you measure the voltage over the component. If the circuit is DE-energized, at that point you are measuring the component's resistance.
The area is given by:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
The area of the base is:
Ab = (3/2) * (L ^ 2) * (root (3))
Where,
L: side of the hexagon.
Substituting we have:
Ab = (3/2) * (4 ^ 2) * (root (3))
Ab = (3/2) * (16) * (root (3))
Ab = 24raiz (3)
The lateral area is:
Al = (6) * (1/2) * (b) * (h)
Where,
b: base of the triangle
h: height of the triangle
Substituting we have:
Al = (6) * (1/2) * (4) * (6)
Al = 72
The total area is:
A = 24raiz (3) + 72
Answer:
A = 24raiz (3) + 72
Answer:
Step-by-step explanation:
0.75 is equivalent to three quarters, or (3/4).
3/4 would be the fraction. -37 would be the whole number.
Hope this helps.
Answer:
(2) 6x^2+40x +50
Step-by-step explanation:
(4x+10)*(2x+5) = 8x^2 +40+50
minus 2x^2
=6x^2 +40 +50
Answer: tom
Step-by-step explanation:
Tom has moere because if you dvide the passes by complections tom has 2.2 but if you devide ians passes by his complections you would get 2.0
