Answer:
(x/2) - (5/4)y = -[(2x/4) + (5/4)y] = -(1/4)[2x + (5/y)]
Step-by-step explanation: hope this helped please make me brainlest
Answer:
all of it
1to12 I love it it is amazing
Answer:
<em><u>The numbers are 12 and −29.</u></em>
<em><u> </u></em><em><u>Mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>brainlist</u></em>
PQ is the tangent, therefore you can use a theorem: The arc measure is double the amount of the angle the tangent makes.
So: 62/2=31
The ball takes 6 seconds to reach the ground.
<u><em>Explanation</em></u>
Height of the ball after
seconds is represented by....
![f(x)= -16(x^2 -5x-6)](https://tex.z-dn.net/?f=f%28x%29%3D%20-16%28x%5E2%20-5x-6%29)
The height of the ball is 0 feet when it hits the ground. So, for finding the number of second the ball takes to reach the ground, <u>we will just plug
into the above equation and then solve for
.</u>
Thus...
![0=-16(x^2-5x-6)\\ \\ x^2-5x-6=0\\ \\ (x-6)(x+1)=0](https://tex.z-dn.net/?f=0%3D-16%28x%5E2-5x-6%29%5C%5C%20%5C%5C%20x%5E2-5x-6%3D0%5C%5C%20%5C%5C%20%28x-6%29%28x%2B1%29%3D0)
Using zero-product property....
![x-6=0\\ x=6](https://tex.z-dn.net/?f=x-6%3D0%5C%5C%20x%3D6)
and
(Negative value is ignored as time can't be negative)
So, the ball takes 6 seconds to reach the ground.