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lys-0071 [83]
3 years ago
13

Which 6 Animal exhibits will I visit?

Mathematics
1 answer:
Marianna [84]3 years ago
6 0

Answer:

all of it

1to12 I love it it is amazing

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A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
4 years ago
Please help! Could you answer all!?
Brums [2.3K]

Answer:

1.) 48

2.) 65

3.) 36

Step-by-step explanation:

1.)     If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.

2.)     This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.

3.) .     This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.

3 0
3 years ago
Read 2 more answers
The shaded region in the graph represents the solutions of this system of linear inequalities:
kotegsom [21]

Answer:

y

y\leq 2x+3

Step-by-step explanation:

step 1

Find the equation of the solid line

From the graph take the points (0,3) and (4,11)

Find the slope

m=(11-3)/(4-0)\\m=8/4=2

The equation of the solid line in slope intercept form is equal to

y=mx+b

we have

m=2

b=3 ----> the y-intercept is the point (0,3)

substitute

y=2x+3

therefore

The inequality is

y\leq 2x+3

step 2

Find the equation of the dashed line

The slope is given

m=4

From the graph take the y-intercept (0,-5)

The equation of the solid line in slope intercept form is equal to

y=mx+b    

we have

m=4

b=-5

substitute

y=4x-5

therefore

The inequality is

y

because the shaded region is below the dashed line

therefore

The system of inequalities is

y

y\leq 2x+3

8 0
3 years ago
A number subtracted from 11 is the quotient of -20 and -2. Find the number.
Troyanec [42]

Answer:

1

Step-by-step explanation:

-20 divided by -2 is the same as 20 divided by 2, which is 10. 11-10=1 so the answer is 1.

8 0
3 years ago
Anyone know ??? i need help badly right now
Brilliant_brown [7]

Answer:

Answer is A 520mm²

I hope you like it

3 0
3 years ago
Read 2 more answers
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