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3 years ago

7

Given the identity tanX=sinXcosX and the relationship between the sine and cosine of complementary angles, what is tan (90°− A)?

2 answers:

lana [24]3 years ago

8 0

Answer:

Step-by-step explanation:

Mumz [18]3 years ago

4 0

Note tanx = sinx / cosx. What you typed is wrong.

For complementary Angles, that is Angles that add up to 90 degrees.
For example 60 and 30 are complementary. 20 and 70 are also complementary, same is 40 and 50. That is because they both add up to 90.

For Complementary Angles:

sinx = cos(90 - x)
cosx = sin(90 -x)
tanx = cot(90 -x)
cotx = tan(90 -x). cotx = 1/tanx

Therefore tan(90-A) = cotA.

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Help, please!!! Coordinate planes: find the distance. Thanks for helping!

ruslelena [56]

Answer:

The answer would be 11.3

Step-by-step explanation:

All you have to do is figure out how far one is from the other so from 7.8 I went back to 0 of course the Y coordinate stays the same. So then you get the -3.5 make it a positive so just 3.5 and then add to 7.8 to get 11.3

Hope this helped.

A brainliest is always appreciated.

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2 years ago

What is the simplified version for these 4 ?

VladimirAG [237]

1. -3x + -6
2. -3x + 9
3. 2x - 6
4. -2x + 6

here u go

3 0

3 years ago

During a business trip, an individual stopped at two rest stops. In the parking lot of the first rest stop, they counted 20 cars

olganol [36]

Answer

given,

on first stop

number of car = 20 and number of trucks = 18

on second stop

number of car = 18 and number of trucks = 10

we need to calculate which rest stop has higher ratio of car to truck.

Rest Stop 1

ratio= r₁ = $\dfrac{cars}{trucks}$

r₁ = $\dfrac{20}{18}$

r₁ = $\dfrac{10}{9}$

Rest Stop 2

ratio= r₂ = $\dfrac{cars}{trucks}$

r₂ = $\dfrac{18}{10}$

r₂= $\dfrac{9}{5}$

hence, r₂ > r₁

rest stop 2 has more car to truck ratio than rest stop 1

3 0

2 years ago

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago

Lillie jogs 1/2 mile in 1/10 hour what is Lilli's rate in miles per hour

Goshia [24]

U technecally wrote the answer

6 0

3 years ago

Read 2 more answers