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3 years ago

The Temperature at 12 noon was 14° C above zero. If it decreases at the

Mathematics

1 answer:

iogann1982 [59]3 years ago

5 0

Answer:

-16

Step-by-step explanation:

you just subtract 2 each hour

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Is -3.4 closer to -2 or -4? I need to round it to find the answer, but I don't know which way.

MA_775_DIABLO [31]

Answer:

-4

Step-by-step explanation:

its closer to -4

6 0

3 years ago

Simplify <br> 2x x y x 3

nikitadnepr [17]

Which is it
2x times y times 3 = 6xy
or,
2xxyx3= 6x^3y

7 0

3 years ago

Will mark brainliest if correct (surface area question)

I am Lyosha [343]

Answer:

535

Step-by-step explanation:

8 x 7 = 56

15 x 17 = 255 . 255 / 2 = 127.5

15 x 7 = 105

17 x 7 = 119

119 + 105 + 127.5 + 127.5 + 56 = 535

6 0

3 years ago

The function f(x) has a vertical asymptote at x = [BLANK].

kolezko [41]

Answer:

-1

Step-by-step explanation:

Based on the photo the asymptote will be x= - 1 because it is approaching it but never touching it

3 0

3 years ago

A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the

3241004551 [841]

Answer:

$h(t)=-16t^2+85t+28$ is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28 feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: $h(t)=\dfrac{1}2gt^2+v_0t+h_0$

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity ( $v_0=85\ ft/s$ )

h ⇒ Initial height ( $h_0=28\ feet$ )

h(t) ⇒ function of height at any time t

Substitute the given values into formula

$h(t)=\frac{1}{2}(-32)t^2+(85)t+28$

$h(t)=-16t^2+85t+28$

D is correct.

6 0

4 years ago

Read 2 more answers