What should you do first in solving the quadratic equation? x² + 18x + 81 = 25

Mathematics

1 answer:

N76 [4]2 years ago

3 0

Answer:

x= -4,-14

Step-by-step explanation:

Try first to solve the equation by factoring. Be sure that your equation is in standard form before you start your factoring attempt.

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1/2 + n = 0, 2/3 + n = 0 And explain

Zepler [3.9K]

So we can subsitute since they all equatl zero
1/2+n=0=2/3+n
1/2+n=2/3+n
subtract n from both sides
1/2=2/3
false statement
therefor there is no solution

4 0

3 years ago

Cuanto es 1 sobre 3 de 15?

Ivenika [448]

Answer:

Cinco es en quince 3 veces igualmentes, 1 vez es uno sobre tres de 15.

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2 years ago

The larger of two consecutive odd integers is three times the smaller. What is their sum?

Darya [45]

X=y+2
x=3y
2x=4y+2
4y+2=2(y+2)
4y+2=2y+4
2y+2=4
2y=2
y=1
x=3
1+3=4

Their sum is 4

Hope this helps :)

4 0

2 years ago

On the last day of vacation, the Hernandez family drove 252 miles from a state park to their home. That drive covered 35% of the

aleksklad [387]

Answer:

720 miles

Step-by-step explanation:

We are given a distance and a fraction of the total that it represents. This lets us write the relation ...

252 = 0.35D . . . . . . where D is the total distance traveled

252/0.35 = D = 720 . . . . divide by the coefficient of D

The Hernandez family traveled 720 miles during their vacation.

7 0

1 year ago

W(1,8),X(7,8),Y(4,5), and Z(1,2) select all methods you can use to prove WYZ is congruent to WYX

marin [14]

The distance between two points (x₁,y1),(x₂,y₂) is d
$d= \sqrt{(x2-x1)^2 + (y2-y1)^2}$

For the given problem we have
W(1,8),X(7,8),Y(4,5), and Z(1,2)

The length of WY = $\sqrt{(4-1)^2 + (5-8)^2}$ = 3√2
The length of WX = $\sqrt{(7-1)^2 + (8-8)^2}$ = 6
The length of WZ = $\sqrt{(1-1)^2 + (2-8)^2}$ = 6
The length of XY = $\sqrt{(4-7)^2 + (5-8)^2}$ = 3√2
The length of ZY = $\sqrt{(1-4)^2 + (2-5)^2}$ = 3√2

∴ WX = WZ ⇒⇒⇒ proved
XY = ZY ⇒⇒⇒ proved
WY = WY ⇒⇒⇒ reflexive property

∴ ΔWYZ is congruent to ΔWYX by SSS method

5 0

2 years ago