Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
Answer:
1. 5040
2. 20
Step-by-step explanation:
1. using the formula for permutation
nPr=n!/(n-r)!
10P4 = 10!/(10-4)!
=10*9*8*7*6!/6!
then we are left with
=10*9*8*7
=5040
2.using the formula for combination
nCr=n!/(n-r)!r!
6C3=6!/(6-3)!3!
=6*5*4*3!/3!3!
=6*5*4/3*2*1
=20
Answer:
363
Step-by-step explanation:
Formula for area of a circle
A = πr^2
Where r = radius
The circle has a given radius of 11
To find the area of the circle we simply substitute r in the formula with the value of the radius (11)
( Also note that the question says to use 3 for π )
A = πr^2
π = 3
r = 11
Substitute values in formula
A = (3)(11)^2
11^2 = 121
A = 121(3)
121(3) = 363
A = 363
Answer:
x=7
Step-by-step explanation:
potato^3
