Perimeter of a quarter circle is 17.85 what is the quarter circles radius

Mathematics

1 answer:

givi [52]3 years ago

4 0

The radius of the given circle is 2.84 units

Step-by-step explanation:

Step 1 :

Given

The perimeter of a quarter table is 17.85

We need to find the circle's radius.

Step 2 :

The circle's perimeter is given by the formula, 2 $\pi$ r where r represents the circle's radius

So from this we have ,

2 $\pi$ r = 17.85

We can determine the radius by dividing the perimeter value by 2 $\pi$

= > r = 17.85 divided by 2 $\pi$ r

= 2.84 [ taking $\pi$ = $\frac{22}{7}$ ]

Step 3 :

Answer :

The radius of the given circle is 2.84 units

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Find the perimeter of the polygon. Round your answer to the nearest tenth.

lubasha [3.4K]

Answer:

Perimeter is 38.8 units and approximately 39 units

Step-by-step explanation:

Given: Graph

To find: perimeter of the polygon

Solution:

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As per the graph,

point P is (-2,11)

point Q is (-4,6)

point R is (2,0)

point S is (1,7)

point T is (8,7)

$PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units$