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STatiana [176]
3 years ago
13

Which polynomial correctly combines the like terms and expresses the given polynomial in standard form? 8mn5 – 2m6 + 5m2n4 – m3n

3 + n6 – 4m6 + 9m2n4 – mn5 – 4m3n3
Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

-6m^{6}+n^{6}+7mn^{5}+14m^{2}n^{4}-5m^{3}n^{3}

Step-by-step explanation:

given polynomial is:

8mn^{5}-2m^{6}+5m^{2}n^{4}-m^{3}n^{3}+n^{6}-4m^{6}+9m^{2}n^{4}- mn^{5}-4m^{3}n^{3}

write similar terms together,

-2m^{6}-4m^{6}+n^{6}+8mn^{5}-mn^{5}+5m^{2}n^{4}+9m^{2}n^{4}-m^{3}n^{3}-4m^{3}n^{3}

-6m^{6}+n^{6}+7mn^{5}+14m^{2}n^{4}-5m^{3}n^{3}

Hence, polynomial in standard form -6m^{6}+n^{6}+7mn^{5}+14m^{2}n^{4}-5m^{3}n^{3}

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A bottle of has a capacity of 0.43 L. How many milliliters of shampoo does the bottle contain (1 L = 1000 mL
jenyasd209 [6]

Answer:

1 = 1000

0.43 L = _________ mL

0.43 * 1000 = 430 mL

<em><u></u></em>

<em><u>430 mL is the answer.</u></em>

<em><u></u></em>

<em><u>Hope this helps</u></em>

4 0
2 years ago
Jean wrote two correct variable expressions to represent the phrase “the quotient of a number and 3.”
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3 years ago
Read 2 more answers
I need help show work<br> ill mark brainliest​
Archy [21]

Answer:

The population will be 896 turtles 6 years later ⇒ B

Step-by-step explanation:

The exponential increasing formula is y = a(1+r)^{x}, where

  • y is the new value
  • a is the initial value
  • r is the rate of increase in decimal
  • x is the time in years

∵ There are 300 turtles

∴ a = 300

∵ The population of the turtles exponentially increases 20% each year

∴ r = 20%

→ Divide it by 100 to change it to decimal

∵ 20% = 20 ÷ 100 = 0.2

∴ r = 0.2

∵ The time is 6 years

∴ x = 6

→ Substitute these values in the exponential formula above

∵ y = 300(1+0.2)^{6}

∴ y = 300(1.2)^{6}

∴ y = 895.7952

→ Round it to the nearest whole number

∴ y = 896

∴ The population will be 896 turtles 6 years later

7 0
3 years ago
Find the logarithmic function y = logbx that passes through the points
katovenus [111]

b\in(0,\ 1)\ \cup\ (1,\ \infty)\\x > 0\\y\in\mathbb{R}\\--------------------------\\\\y=\log_bx\\\\For\ (1,\ 0)\to x=1,\ y=0.\ Substitute:\\\\\log_b1=0\to b^0=1\to b\in(0,\ 1)\ \cup\ (1,\ \infty)\\\\For\ (116,\ 2)\to x=116,\ y=2.\ Substitute:\\\\\log_b116=2\to b^2=116\to b=\sqrt{116}\\\to b=\sqrt{4\cdot29}\to b=\sqrt4\cdot\sqrt{29}\to b=2\sqrt{29}\\\\For\ (4,\ -1)\to x=4,\ y=-1.\ Substitute:\\\\\log_b4=-1\to b^{-1}=4\to b=\dfrac{1}{4}

Different values of b.

<h3>Answer: There is no logarithmic function whose graph goes through given points.</h3><h3 />

Maybe the second point is \left(\dfrac{1}{16},\ 2\right)

Substitute:

\log_b\dfrac{1}{16}=2\to b^2=\dfrac{1}{16}\to b=\sqrt{\dfrac{1}{16}}\to b=\dfrac{1}{4}

<h3>Then we have the answer:</h3>

\boxed{y=\log_{\frac{1}{4}}x}

6 0
3 years ago
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