Step-by-step explanation:
<DBA=180 since it is a straight line
<HBA=73
mHG=73
Answer:
289 m²
Step-by-step explanation:
First find the area of the flower bed
A=πr²= (3.14)(9.5)² = 283.385
Then get the area of everything including the sidewalk
A=πr²= (3.14)(13.5)² = 572.265
Then subtract and you'll get the area of just the sidewalk
572.265 - 283.385 = 288.88m²
Answer:
Step-by-step explanation:
REcall the following definition of induced operation.
Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.
So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.
For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).
Case SL2(R):
Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So
.
So AB is also in SL2(R).
Case GL2(R):
Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So
.
So AB is also in GL2(R).
With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).
It isn't true at all it isn't a question even
Answer:
may be its -6 units
Step-by-step explanation:
because if you count the number it will be-6