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2 years ago

The hypotenuse of 30-60-90 triangle is a length of 32. What will be the length of the 2 legs?

Mathematics

1 answer:

katovenus [111]2 years ago

5 0

16 and 16sqrt(3) because of the 30-60-90 rule

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A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on three numbers pays 11 to 1 (that is, if you bet $1 and one of

OLga [1]

Answer:

You are expected to lose $0.05 (or win -$0.05)

Step-by-step explanation:

Since the roulette wheel has the numbers 1 through 36, 0, and 00, there are 38 possible outcomes.

In this bet, you are allowed to pick 3 out of the 38 numbers. Thus, your chances of winning (P(W)) and losing (P(L)) are:

$P(W)=\frac{3}{38}\\P(L) = 1 - P(W)\\P(L) = \frac{35}{38}\\$

The expected value of the bet is given by the sum of the product of each outcome pay by its probability. Winning the bet means winning $11 while losing the bet means losing $1. The expected value is:

$EV = (11*\frac{3}{38}) -(1*\frac{35}{38})\\EV = -\$0.0525$

Therefore, with a $1 bet, you are expected to lose roughly $0.05

5 0

2 years ago

If you break someone's neck can you go to jail for that?

melomori [17]

Answer:

Yes.

Step-by-step explanation:

If you do not have a valid reason like it was for self-defense, then you absolutely can go to jail.

4 0

2 years ago

Read 2 more answers

Can somebody help me please

Mrac [35]

Answer:
A=(1/2)BxH
10x6=60m

4 0

2 years ago

Read 2 more answers

If your test increased by 14 points, what percent did you increase if there were 50 questions in total? show work

solmaris [256]

Increase = 14
Total =50
Percentage increase = 14/50 x 100 = 28%

8 0

2 years ago

$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent

photoshop1234 [79]

$\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
\\
\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
\\
\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}$

$A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
\\
\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
\\
\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
\\
\Rightarrow A\approx 66328.68$

So the amount after 21 years is: $66328.68

7 0

3 years ago